1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
liq [111]
3 years ago
11

Which of the following has the lowest Ka?a. carbonic acid b. dihydrogen phosphate c. phosphoric acid d. bicarbonate

Chemistry
1 answer:
Naya [18.7K]3 years ago
7 0

Explanation:

A compound or molecule which will have least dissociation and that is not able to given hydrogen ion easily upon dissociation will also have a low value of K_{a}.

Dissociation of the given compounds or species will be as follows.

 H_{2}CO_{3} \rightleftharpoons H^{+} + HCO^{-}_{3}

 H_{2}PO^{-}_{4} \rightleftharpoons H^{+} + HPO^{-}_{4}

 H_{3}PO_{4} \rightleftharpoons H_{+} + H_{2}PO^{-}_{4}

As, chemical formula of bicarbonate is HCO^{-}_{3} and due to the presence of a negative charge it is difficult to lose a positively charged hydrogen ion. This is because oppositely charged ions will be bonded by strong force of attraction.

Hence, it will not easily lose a hydrogen ion due to which bicarbonate has the lowest K_{a}.

Thus, we can conclude that out of the given species bicarbonate has the lowest K_{a}.    

You might be interested in
A good scientist does not let his or her personal beliefs or _____,influence their study
arlik [135]
The missing word, is approach.

Hope I helped,
-CSX
4 0
3 years ago
Select the formula for the following acid: Carbonic Acid
Nina [5.8K]

Answer: 106

Explanation:

Follow PEMDAS. 7x12 = 84

84 + 13 = 97

97 + 9 = 106

4 0
3 years ago
Balance the equation xcl2(aq)+agno3(aq)=x(no3)2(aq)+agcl(s)
lisabon 2012 [21]

Explanation:

XCl _{2(aq)} + 2AgNO _{3(aq)}→X(NO _{3}) _{2(aq)}   +2 AgCl _{(s)}

6 0
3 years ago
Read 2 more answers
Determine the ph of a 0.00598 m hclo4 solution. 1.777 6.434 7.566 2.223 3.558
Black_prince [1.1K]
Answer: 2.223
Explanation:
HClO4, also known as perchloric acid, is a very strong. This means we can assume that complete dissociation occurs.
This means that:
[H+] = [HClO4] = <span>0.00598

pH = -log[H+]
pH = -log[</span><span>0.00598] = 2.223

Note: The base of the log is 10 (conventionally we don't write the base if it is 10)</span>
4 0
4 years ago
Read 2 more answers
How many moles are in 5.72 grams of iron (II) chloride
densk [106]

Answer:

0.0451 mol FeCl₂

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

5.72 g FeCl₂

<u>Step 2: Identify Conversions</u>

Molar Mass of Fe - 55.85 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of FeCl₂ - 55.85 + 2(35.45) = 126.75 g/mol

<u>Step 3: Convert</u>

<u />5.72 \ g \ FeCl_2(\frac{1 \ mol \ FeCl_2 }{126.75 \ g \ FeCl_2} ) = 0.045128 mol FeCl₂

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.045128 mol FeCl₂ ≈ 0.0451 mol FeCl₂

8 0
3 years ago
Other questions:
  • I really need help with this I would really appreciate it​
    5·1 answer
  • What has neutral charge
    8·2 answers
  • A vessel of volume 22.4 dm3 contains 20 mol h2 and 1 mol n2 ad 273.15 k initially. All of the nitrogen reacted with sufficient h
    8·1 answer
  • Which distance measures 5 units? the distance between points W and X the distance between points X and Y the distance between po
    5·2 answers
  • What type of reaction 2Mg+O2→2MgO
    15·1 answer
  • 0.25 mol of nitric acid is used to make a 0.10 M nitric acid solution. What is the total volume of nitric acid in liters
    10·1 answer
  • Which of the following best describes the formation of plasma?
    6·1 answer
  • (WILL MARK AS BRAINLIEST!)
    9·1 answer
  • Does anyone want free point? Just comment whatever٩(ˊᗜˋ)و
    10·2 answers
  • Calculate the mass of 2.5 mol of Iron (111) oxide<br> Fe2O3
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!