To remove one electron from singly ionized helium, will require approximately 54.4 eV or 8.72 1020 J of energy.
The amount of energy required by an isolated, gaseous molecule in the electronic state of the ground to absorb in order to discharge an electron and produce a cation has been known as the ionization energy. The amount of energy required for every atom in a mole to drop one electron is most often given as kJ/mol.
Anything that causes electrically neutral atoms and molecules to gain or lose electrons in order to become electrically charged atoms as well as molecules .
Therefore, the "To remove one electron from singly ionized helium, will require approximately 54.4 eV or 8.72 1020 J of energy."
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Answer:
Paddy
Explanation:
he word paddy is used to describe an artificial pond with raised edges which are used for agriculture.
The reaction equation is:
Li + Br → LiBr
39 grams of Li = 39 / 7 = 5.57 moles of lithium
41.5 grams of Br = 41.5 / 80 = 0.52 mole of bromine
2 H2 + O2 = 2 H2O
1 mole O2 --------------- 2 moles H2O
13.35 moles O2 -------- ( moles H2O)
moles H2O = 13.35 x 2 / 1
<span>= </span>26.7 moles of H2O
<span>hope this helps!</span>