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Nana76 [90]
3 years ago
7

Balance the equation xcl2(aq)+agno3(aq)=x(no3)2(aq)+agcl(s)

Chemistry
2 answers:
Fittoniya [83]3 years ago
8 0

Answer:

XCl2(aq) + 2AgNO3(aq) --------> X(NO3)2(aq) + 2AgCl(s)

Explanation:

The rule guiding he balancing of reaction equations is that the number of atoms of each element on both sides of the reaction equation must be the same.

In order to balance this equation, this rule must be applied. The balanced reaction equation therefore becomes;

XCl2(aq) + 2AgNO3(aq) --------> X(NO3)2(aq) + 2AgCl(s)

We can see by conducting an atom count that the number of atoms of each element on both sides of reaction equation is the same hence the equation is balanced.

lisabon 2012 [21]3 years ago
6 0

Explanation:

XCl _{2(aq)} + 2AgNO _{3(aq)}→X(NO _{3}) _{2(aq)}   +2 AgCl _{(s)}

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Simplest ratio
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Molecular formula = n Empirical formula.

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2 years ago
What are the uses of polythene?
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8 0
3 years ago
Explain your reasoning. Match each explanation to the appropriate blanks in the sentences on the right.
skelet666 [1.2K]

Answer:

A (I_2(g), Br_2 (g), Cl_2 (g), F_2 (B): The ranking can best be explained by the trend entropy decreases as 5. molar mass decreases.

B (H_2O_2 (g), H_2S(g), H_2O(g): The ranking can best be explained by the decreases a trend entropy decreases as 3. molar mass and structure complexity decreases.

C. (C(s, amorphous), C(s, graphite), C(s, diamond): The ranking can best be explained by the trend entropy decreases as 4. structure complexity decreases.

Explanation:

Hello.

In this case, we can understand a higher entropy when more disorder is present and a lower entropy when less disorder is present, thus:

A (I_2(g), Br_2 (g), Cl_2 (g), F_2 (B): The ranking can best be explained by the trend entropy decreases as 5. molar mass decreases since iodine has the greatest molar mass (254 g/mol) and fluorine the least molar mass (38 g/mol).

B (H_2O_2 (g), H_2S(g), H_2O(g): The ranking can best be explained by the decreases a trend entropy decreases as 3. molar mass and structure complexity decreases since hydrogen peroxide weights 34 g/mol as well as hydrogen sulfide but the peroxide has more bonds (more complex, higher entropy).

C. (C(s, amorphous), C(s, graphite), C(s, diamond): The ranking can best be explained by the trend entropy decreases as 4. structure complexity decreases since diamond has a well-ordered structure and amorphous carbon has a very disordered one.

Best regards.

4 0
2 years ago
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