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Ipatiy [6.2K]
3 years ago
5

Find the values of A B C AND D of 4x^2 (2x^3+5x)= Ax^B +Cx^D

Mathematics
1 answer:
iren2701 [21]3 years ago
3 0

The values are A=8, B=5, C= 20 and D=3

Explanation:

The expression is 4x^{2} (2x^{3} +5x)=Ax^{B} +Cx^{D}

Simplifying, we get,

8x^{5} +20x^3=Ax^{B} +Cx^{D}

Since, both sides of the expression are equal, we can equate the corresponding values of A, B, C and D.

Thus, we get,

8 x^{5}=A x^{B} ⇒ A=8 and B=5

Also, equating, 20 x^{3}=C x^{D}, we get,

C=20 and D=3

Thus, the values are A=8, B=5, C= 20 and D=3

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