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3 years ago

If b = 5, what is b to the square root of 3

Mathematics

1 answer:

liubo4ka [24]3 years ago

6 0

Is 125 because u need to take the 5 and add 3 on the top

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Descompuneti in factori. x^2+4x-5=?

Lapatulllka [165]

Assume that,
x^2+4x-5 = 0 .......(1)
Then, x^2+4x-5 = 0 x^2+5x-1x-5 =0
x(x+5)-1(x+5) = 0
(x+5) (x-1) = 0
We get x=-5 and x=1
Sub x=-5 in equ (1)
(-5)^2+4(5)-5 = 0
-25+20-5 = 0
-25+25= 0
0 = 0
Sub x=1 in equ (1) (1)^2+4(1)-5 = 0
1+4-5 = 0 5-5 = 0
0 = 0
Therefore x value is -5 and 1

3 0

3 years ago

Please help If you know the answer!!

prisoha [69]

Answer:

-3 +8a

Step-by-step explanation:

(3-8a) *(-1)

Distribute

3*-1 -8a*-1

-3 +8a

4 0

3 years ago

Can someone help me

erik [133]

Answer:

6 < x < 23.206

Step-by-step explanation:

To properly answer this question, we need to make the assumption that angle DAC is non-negative and that angle BCA is acute.

The maximum value of the angle DAC can be shown to occur when points B, C, and D are on a circle centered at A*. When that is the case, the sine of half of angle DAC is equal to 16/22 times the sine of half of angle BAC. That is, ...

(2x -12)/2 = arcsin(16/22×sin(24°))

x ≈ 23.206°

Of course, the minimum value of angle DAC is 0°, so the minimum value of x is ...

2x -12 = 0

x -6 = 0 . . . . . divide by 2

x = 6 . . . . . . . add 6

Then the range of values of x will be ...

6 < x < 23.206

_____

* One way to do this is to make use of the law of cosines:

22² = AB² + AC² -2·AB·AC·cos(48°)

16² = AD² + AC² -2·AD·AC·cos(2x-12)

The trick is to maximize x while satisfying the constraints that all of the lengths are positive. This will happen when AB=AC=AD, in which case the equations be come ...

22² = 2·AB²·(1-cos(48°))

16² = 2·AB²·(1 -cos(2x-12))

The value of AB drops out of the ratio of these equations, and the result for x is as above.

4 0

3 years ago

Read 2 more answers

Which line is perpendicular to the line y=-1/3x-2 and passes through point (1,4)

xxMikexx [17]

Answer:

Option 3) y = 3x+1

Step-by-step explanation:

Given equation is:

y = $-\frac{1}{3} x -2$

Perpendicular => It will have a slope of negative reciprocal to this slope

So the ⊥ line has a slope = m = 3

Now,

Point = (x,y) = (1,4)

So, x = 1, y = 4

Putting this in slope intercept form to get b

=> $y = mx+b$

=> 4 = (3)(1) + b

=> b = 4-3

=> b = 1

Now, Putting m and b in the slope intercept form to get the required equation:

=> y = 3x+1

4 0

3 years ago

Read 2 more answers

A tree that is 14 feet tall casts a shadow that is 30 feet long. Find the angle of the elevation from the top of the shadow to t

Umnica [9.8K]

Let x = angle we must find

tan x = 14/30

arctan(tan x) = arctan(14/30)

x = 25.0168934781

Answer: 25 degrees

8 0

3 years ago