320 ft in perimeter and 200 ft in area
suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z = 
= 
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438
your answer is C. substraction
Answer:
<h2>
-9/22t</h2>
Step-by-step explanation:
Just do -4/22-5/22 = 9/22 and just add a t, which is 9/22t.
Answer:
8
Step-by-step explanation:
Hope this helps :)