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lesantik [10]
3 years ago
7

Carl puts 1.10 in his penny bank every day in the month of July. His total savings was 55at the end of June. What’s the best est

imate for Carl’s savings at the end of July
Mathematics
2 answers:
AfilCa [17]3 years ago
8 0

Answer:

About 85 is the answer

Makovka662 [10]3 years ago
5 0
Just take 55 and add 1.10 times the amount of days in july
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A triangle has a 90 degree angle and two sides that measure 5cm in length. Read the statements
mihalych1998 [28]

Answer:

Yes   (True)

Step-by-step explanation:

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2 years ago
Pls give me an explanation on how to do this so I can do the other problems on my own​
galina1969 [7]

Answer:

Everything on the left of the 0 is negative and everything to the right of 0 is positive

Step-by-step explanation:

8 0
3 years ago
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8 1/2 + 17 2/3 + 12 1/6 <br><br> what is the answer??
Nuetrik [128]

Answer:

the answer is in point 117.967

3 0
2 years ago
Help please!!!
katovenus [111]

Answer:

x = \frac{7+\sqrt{47}\times i }{4}

Step-by-step explanation:

<u>To solve quadratic systems,we always substitute one variable in terms if the other and then solve the equation.</u>

x + 2y = 6                                 ---------------(1)

y - 5 = (x-2)^{2}         ---------------(2)

y = (x-2)^{2} + 5         ---------------(3)

Substitute (3) in (1) ,

x + 2( (x-2)^{2} + 5 ) = 6

(a + b)^{2} =a^{2} + 2ab + b^{2}

x + 2( x^{2} - 4x + 4 + 5 ) = 6

2x^{2} - 7x + 12=0      --------------(4)

The roots of the quadratic equation ax^{2}  +bx+c is

x = \frac{(-b) + \sqrt{(-b)^{2}-4 \times ac }  }{2 \times a}  -----------(5)

According to equation (5),solution of (4) is

x =  \frac{7 + \sqrt{(-7)^{2}-4 \times 24 }  }{2 \times 2}

x =  \frac{7+\sqrt{49-96}}{4}

x = \frac{7+\sqrt{47}\times i }{4}

 

4 0
3 years ago
Which transformations have been applied to the graph of f(x) = x2 to produce the graph of g(x) = –5x2 + 100x – 450? Select three
RSB [31]

Answer:

The graph of f(x) is shifted up 50 units

The graph of f(x) is shifted right 10 units

The graph of f(x) is reflected over the x-axis

Step-by-step explanation:

we have

f(x)=x^{2}

This is a vertical parabola open upward

The vertex is a minimum

The vertex is the origin (0,0)

g(x)=-5x^{2}+100x-450

This is a vertical parabola open downward

The vertex is a maximum

The first thing to note is that fx) is a parabola that opens up and g(x) opens down, so a reflection across the x-axis must have been applied.

Find the vertex of g(x)

Convert to vertex form

g(x)=-5x^{2}+100x-450

Complete the square

g(x)=-5(x^{2}-20x)-450

g(x)=-5(x^{2}-20x+100)-450+500

g(x)=-5(x^{2}-20x+100)+50

g(x)=-5(x-10)^{2}+50

The vertex is the point (10,50)

so

To translate the vertex of (0,0) to (10,50)

The rule of the translation is

(x,y) ------> (x+10,y+50)

That means ----> The translation is 10 units at right and 50 units up

therefore

The transformations are

The graph of f(x) is shifted up 50 units

The graph of f(x) is shifted right 10 units

The graph of f(x) is reflected over the x-axis

5 0
3 years ago
Read 2 more answers
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