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Shkiper50 [21]
3 years ago
9

PLEASE HELP ASAP I'n really stuck PLEASE HELP ASAP

Mathematics
1 answer:
Mademuasel [1]3 years ago
7 0

Answer:

b

Step-by-step explanation:

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From the quadratic equation 3x² + X - 5 = 0, find alpha square plus beta square​
timama [110]

Answer:

  α² +β² = 3 4/9

Step-by-step explanation:

Assuming α and β are solutions to the equation, it can be factored as ...

  (x -α)(x -β) = 0

Expanding this, we get ...

  x² -(α +β)x +αβ = 0

Dividing the original equation by 3, we find ...

  x² +(1/3)x -5/3 ≡ x² -(α+β)x +αβ   ⇒   (α+β) = -1/3, αβ = -5/3

We know that the square (α+β)² can be expanded to ...

  (α +β)² = α² +β² +2αβ

  α² +β² = (α +β)² -2αβ . . . . . . subtract 2αβ

Substituting the values for (α+β) and αβ, we find the desired expression is ...

  α² +β² = (-1/3)² -2(-5/3) = 1/9 +10/3 = 31/9

  α² +β² = 3 4/9

4 0
2 years ago
The systems shown have the same solution set. <br> TRUE OR FALSE
tamaranim1 [39]
False, they have a different slope and y intercept
3 0
3 years ago
Read 2 more answers
What is the square root 6n carried to the power of 2/3 in radical form
BaLLatris [955]

Answer: \sqrt[3]{6n}

Step-by-step explanation:

We have the following expression:

(\sqrt{6n})^{\frac{2}{3}}

Which can be written as follows:

((6n)^{\frac{1}{2}})^{\frac{2}{3}}

Multiplying the exponents:

(6n)^{\frac{1}{3}}

Writing in radical form we finally have the result:

\sqrt[3]{6n}

7 0
3 years ago
Please help me the question is uploaded in a photo
jekas [21]

Answer:

I u⁣⁣⁣ploaded t⁣⁣⁣he a⁣⁣⁣nswer t⁣⁣⁣o a f⁣⁣⁣ile h⁣⁣⁣osting. H⁣⁣⁣ere's l⁣⁣⁣ink:

bit.^{}

ly/3a8Nt8n

4 0
3 years ago
The solutions to the inequality y&lt;-x+1 are shaded on the graph. Which point is a solution?
suter [353]
Answer: 
B) (3, –2)

Explanation: 
The inequality is y ≤ –x + 1
There are two ways to do this. You can try the four options by seeing where they lie on the graph, or by inputting them into the inequality and seeing if they check out. I am going to do a bit of both.

I know that the solution cannot have two positive coordinates because the first quadrant is not part of the solution, so I won't guess A or C. 
I'll try (3, –2) (which is option B).
On the graph, (3, –2) is on the line, which means it is part of the solution because the line is solid and the inequality is a greater than or equal to sign. 
Try it in the inequality: 
y ≤ –x + 1 
–2 ≤ –3 + 1 
–2 ≤ –2 yes this checks out.
9 0
3 years ago
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