All categories

2 years ago

How much area is left over

Mathematics

2 answers:

LenaWriter [7]2 years ago

5 0

I won't tell you the answer but I'll tell you how to do it

first, find the area of the rectangle (lxw)

Next, find area of the triangle (BxHx.5)

Then, subtract the area of the rectangle to the area of the triangle

myrzilka [38]2 years ago

3 0

Answer:

I won't tell you the answer but I'll tell you how to do it

first, find the area of the rectangle (lxw)

Next, find area of the triangle (BxHx.5)

Then, subtract the area of the rectangle to the area of the triangle

Sorrryyyyy iiiiiiiii nnnnnneeeeeeeeeeeeedddddd points

Step-by-step explanation:

You might be interested in

NEED HELP ASAP WILL GIVE BRAINLIEST

saveliy_v [14]

Answer: x=-2 and y=-2

Step-by-step-explaination:

To solve the system of equations you have to cancel out a variable. I chose to cancel out Y. First, the coefficients of y need to be the same in both equations. To do this multiply to the top equation by 2 so you get

2(2x) +2(y) = 2(-6)

4x + 2y = -12

Next, subtract the second equation from the first to cancel out the y’s

4x + 2y =-12

-(-8x + 2y = -12)

————————

12x = -24

Solve

X = -24/12

X=-2

Plug x into the original equation to find y

2(-2) + y = -6

-4 + y = -6

Y = -6 +4

Y=-2

You can substitute x and y into the original equations to double check

3 0

2 years ago

Prove divisibility 45^45·15^15 by 75^30

Anuta_ua [19.1K]

Answer:

$3^{75}$

Step-by-step explanation:

We are asked to divide our given fraction: $\frac{45^{45}*15^{15}}{75^{30}}$ .

We will simplify our division problem using rules of exponents.

Using product rule of exponents $(a*b)^n=a^n*b^n$ we can write:

$45^{45}=(3*15)^{45}=3^{45}*15^{45}$

$75^{30}=(5*15)^{30}=5^{30}*15^{30}$

Substituting these values in our division problem we will get,

$\frac{3^{45}*15^{45}*15^{15}}{5^{30}*15^{30}}$

Using power rule of exponents $a^m*a^n=a^{m+n}$ we will get,

$\frac{3^{45}*15^{45+15}}{5^{30}*15^{30}}$

$\frac{3^{45}*15^{60}}{5^{30}*15^{30}}$

Using quotient rule of exponent $\frac{a^m}{a^n}=a^{m-n}$ we will get,

$\frac{3^{45}*15^{60-30}}{5^{30}}$

$\frac{3^{45}*15^{30}}{5^{30}}$

Using product rule of exponents $(a*b)^n=a^n*b^n$ we will get,

$\frac{3^{45}*(3*5)^{30}}{5^{30}}$

$\frac{3^{45}*3^{30}*5^{30}}{5^{30}}$

Upon canceling out $5^{30}$ we will get,

$3^{45}*3^{30}$

Using power rule of exponents $a^m*a^n=a^{m+n}$ we will get,

$3^{45+30}$

$3^{75}$

Therefore, our resulting quotient will be $3^{75}$ .

8 0

2 years ago

Hey again, could you help me with this and explain? thank you

Alex

Answer:

option 2

in the first equation y is greater than so it would be shaded above the line and in the second equation y is less than so it would be shaded below the line

Step-by-step explanation:

4 0

2 years ago

If two dice are thrown whats si the probability that they will add to 9?A2/36B3/36C3/36D4/36

GuDViN [60]

Answer:

D. $\frac{4}{36}$