A) <span>5x^2-13x-6
1. First, you must find the roots of the quadratic equation, by applying the quadratic formula, which is:
x=-b</span>√(b²-4ac)/2a
<span>
2. The roots are:
x1=3
x2=-2/5
3. Then, you have:
5(x-3)(x+2/5)
4. When you simplify, you obtain:
(x-3)(5x+2)
B) </span>4x^4-28x^3+48x^2<span>
1. First, you must factor the common term, which is 4x</span>^2. Then:
<span>
4x</span>^2(x^2-7x+12)
<span>
2. Now, you must apply the quadratic formula to obtain the roots of the quadratic equation: </span>x^2-7x+12. Then, you have:
x1=4
x2=3
3. Finally, you obtain:
4x^2(x-4)(x-3)
5y-40
5 multiply y and 5 multiply -8
hope this helps !
7x-2x+15=10
5x+15 = 10
- 15 (on both sides, cancels out on the left side)
5x= -5
÷5 (on both sides, cancels out on the left)
x = -1
I hope that helped! ☺♥
Answer:
Step-by-step explanation:
1,4 ,13 , __________, 121
First term = 1
Second term = 1 + 3 = 4
Third term = 4 + 3*3 = 4 + 9 = 13
Fourth term = 13 + 3*3*3 = 13 + 27 = 40
2) 5, 12 , 33 ,_____
First term = 5
Second term = 5 + 7 = 12
Third term = 12 + 7*3 = 12 + 21 = 33
Fourth term = 33 + 7*3*3 = 33 + 63 = 99
Answer:
Third One
Step-by-step explanation: