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2 years ago

15

HelpI need this answer A.S.A.P.

1 answer:

kiruha [24]2 years ago

4 0

Answer:

i think its 31

Step-by-step explanation:

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This is a geometry question, please help me asap!!

stiv31 [10]

Answer: X= 54.9 mm
Explanation: honestly I would never know how to do this and I don’t know how to do this I just put it into a triangle generator and it gave me the correct answer I promise its right

8 0

2 years ago

Which is bigger, a third of 45 or one-sixth c<br> 138?

Ksju [112]

Applying the knowledge of fractions, the bigger one is: one-sixth of 138.

<h3>What are Fractions?</h3>

Fractions can be defined as a part of a digit or number, and are not whole numbers. For example, a third is 1/3, one-sixth is 1/6, which are both fractions.

Therefore, let's evaluate each statement:

1/3 of 45 = 1/3 × 45 = 15

1/6 of 138 = 1/6 × 138 = 23

Therefore, the bigger of the two is: one-sixth of 138.

Learn more about fractions on:

brainly.com/question/17220365

#SPJ1

6 0

1 year ago

Find the distance between the points (3,8) and (11,10)

ikadub [295]

8.24621 is the distance between the points

3 0

2 years ago

Suppose you like to keep a jar of change on your desk. Currently, the jar contains the following: 22 Pennies 27 Dimes 9 Nickels

kap26 [50]

Answer:

$P(Penny\ and\ Dime) = \frac{9}{116}$

Step-by-step explanation:

Given

$Pennies = 22$

$Dimes = 27$

$Nickels = 9$

$Quarters = 30$

Required

$P(Penny\ and\ Dime)$

This is calculated as:

$P(Penny\ and\ Dime) = P(Penny) * P(Dime)$

Since it is a selection without replacement, the computation is:

$P(Penny\ and\ Dime) = \frac{Penny}{Total} * \frac{Dime}{Total-1}$

So, we have:

$P(Penny\ and\ Dime) = \frac{22}{22+27+9+30} * \frac{Dime}{22+27+9+30-1}$

$P(Penny\ and\ Dime) = \frac{22}{88} * \frac{27}{87}$

$P(Penny\ and\ Dime) = \frac{1}{4} * \frac{9}{29}$

$P(Penny\ and\ Dime) = \frac{9}{116}$

5 0

2 years ago

Your school wants to take out an ad in the paper congratulating the basketball team on a successful season, as shown to the rig

iogann1982 [59]

Answer:

$x_1 =-14.43 in, x_2 = 2.426in$

Since the measurement can't be negative the correct answer for this case would be $x =2.426 in$

Step-by-step explanation:

Let's assume that the figure attached illustrate the situation.

For this case the we know that the original area given by:

$A_i = 7 in *5 in = 35in^2$

And we know that the initial area is a half of the entire area in red $A_i = \frac{A_f}{2}$ , so then:

$A_f = 2 A_ i =2*35 = 70$

And we know that the area for a rectangular pieces is the length multiplied by the width so we have this:

$70 = (x+7) (x+5)$

We multiply both terms using algebra and the distributive property and we got:

$70 =x^2 +12 x +5$

And we can rewrite the expression like this:

$x^2 +12 x -35 = 0$

And we can solve this using the quadratic formula given by:

$x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}$

Where $a = 1, b =12 and c=-35$ if we replace we got:

$x = \frac{-12 \pm \sqrt{(12)^2 -4(1)(-35)}}{2*1}$

And the two possible solutions are then:

$x_1 =-14.43 in, x_2 = 2.426in$

Since the measurement can't be negative the correct answer for this case would be $x =2.426 in$

3 0

3 years ago