Find an equation of the plane that contains the points p(5,−1,1),q(9,1,5),and r(8,−6,0)p(5,−1,1),q(9,1,5),and r(8,−6,0).
topjm [15]
Given plane passes through:
p(5,-1,1), q(9,1,5), r(8,-6,0)
We need to find a plane that is parallel to the plane through all three points, we form the vectors of any two sides of the triangle pqr:
pq=p-q=<5-9,-1-1,1-5>=<-4,-2,-4>
pr=p-r=<5-8,-1-6,1-0>=<-3,5,1>
The vector product pq x pr gives a vector perpendicular to both pq and pr. This vector is the normal vector of a plane passing through all three points
pq x pr
=
i j k
-4 -2 -4
-3 5 1
=<-2+20,12+4,-20-6>
=<18,16,-26>
Since the length of the normal vector does not change the direction, we simplify the normal vector as
N = <9,8,-13>
The required plane must pass through all three points.
We know that the normal vector is perpendicular to the plane through the three points, so we just need to make sure the plane passes through one of the three points, say q(9,1,5).
The equation of the required plane is therefore
Π : 9(x-9)+8(y-1)-13(z-5)=0
expand and simplify, we get the equation
Π : 9x+8y-13z=24
Check to see that the plane passes through all three points:
at p: 9(5)+8(-1)-13(1)=45-8-13=24
at q: 9(9)+8(1)-13(5)=81+9-65=24
at r: 9(8)+8(-6)-13(0)=72-48-0=24
So plane passes through all three points, as required.
Answer:
x=1
y=-1/2
Step-by-step explanation:
x+2y=0....(1)
10y=-5.....(2)
From (2) we can find y.
y=-5/10
y=-1/2
Use that in (1)
x+2*(-1/2)=0
x-1=0
x=1
Hello.
First, let the number be r.
5 times r is written like this:
Now, add 45:
Now, the sum of 5r+45 is equal to the sum of 85 and 140:
In order to solve this equation, we need to add 85 and 140:
Now, subtract 45 from both sides:
The last step is to divide both sides by 5:
Therefore, the answer is
I hope it helps.
Have a nice day.
Answer:
See below in bold.
Step-by-step explanation:
1 teaspoon holds 5 ccs so that is 2 teaspoons per dose.
2 teaspoons every 6 hours is 4 * 2 = 8 teaspoons per day.
