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4 years ago

6

Given 7cx + b = a, rearrange the equation for x, in terms of a, b, and c. A) x = 7c a + b B) x = 7c a − b C) x = a + b 7c D) x =

a − b 7c

2 answers:

shepuryov [24]4 years ago

7 0

ANSWER:

7cx + b = a

7cx = a - b

x = ( a - b ) / 7c

Please mark as brainliest if you found this helpful! :)
Thank you <3

nadya68 [22]4 years ago

3 0

Answer:

its d

Step-by-step explanation:

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Answer:

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Read 2 more answers

(1/27)^x-6=27<br><br>Could I please have a step by step as well? Much appreciated!

Andrei [34K]

Answer:

$x = 7$

Step-by-step explanation:

1) Use Division Distributive Property: (x/y)^a = x^a/y^a.

$\frac{1}{ {27}^{x - 8} } = 27$

2) Multiply both sides by 27^x - 8.

$1 = {27} \times 27^{1 + x - 8}$

3) Use the product rule: x^a x^b = x^a+b.

$1 = {27}^{1 + x - 8}$

4) Simplify 1 + x - 8 to x - 7.

$1 = {27}^{x - 7}$

5) Use Definition of Common Logarithm: b^a = x if and only if log<u>b</u><u> </u>(x) = a.

$log_{27}1 = x - 7$

6) Use Change of Base Rule.

$\frac{ log_1 }{ log{27} } = x - 7$

7) Use rule of 1: log 1 = 0.

$\frac{0}{ log_{27}} = x - 7$

8) Simplify 0/log_27 to 0.

$0 = x - 7$

9) Add 7 to both sides.

$7 = x$

10) Switch sides.

$x = 7$

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