Answer:
2kg
Step-by-step explanation:
Let the sum of the other 2 bricks be R. Given that the heaviest brick weighs 2/3 times as much as the other 2 bricks in total, then the weight of the heaviest brick H in terms of the weight of the other 2 will be
H = 2/3 * R
= 2R/3
Given that the 3 bricks weigh 5kg in total then,
2R/3 + R = 5
Multiply through the equation by 3
2R + 3R = 15
5R = 15
Divide both sides by 5
R = 15/5
= 3
The weight of the heaviest brick is 2R/3. Since R = 3, the heaviest block weighs
= 2 * 3/3
= 2kg
Answer:
4.5
Step-by-step explanation:
3 = 9/3
2/3 goes in 9/3 4.5 times
Answer:
B) variables
Step-by-step explanation:
Answer:
Step-by-step explanation:
8
Answer:
Step-by-step explanation:
d(t)=-2t^2+9t+18
calculate the derivate : f'(t) = - 4t+9
f'(t) = 0 : - 4t+9= 0 so t = 9/4
the maximum value is f(9/4) = ....... continue