Question

Which statements are true about the solid, which has a length of

Answer 1

Answer : The correct options are:

The perimeter of one of its faces is 10 inches.

The area of one of its faces is 6 inch².

The area of one of its faces is 12 inch².

The volume of the solid is 36 inches³.

Step-by-step explanation :

Formula used for perimeter of one face (rectangle) is:

Perimeter = 2(l+b)

Perimeter = 2(b+h)

Perimeter = 2(l+h)

Formula used for area of one face (rectangle) is:

Area = l × b

Area = b × h

Area = l × h

Formula used for volume of solid (cuboid) is:

volume of solid = l × b × h

Given:

l = length = 6 inches

b = width = 3 inches

h = height = 2 inches

Now we have to calculate the perimeter of one face.

Perimeter = 2(l+b)

Perimeter = 2(6+3) = 18 inch

Perimeter = 2(b+h)

Perimeter = 2(3+2) = 10 inch

Perimeter = 2(l+h)

Perimeter = 2(6+2) = 16 inch

Now we have to calculate the area of one face.

Area = l × b

Area = 6 × 3 = 18 inch²

Area = b × h

Area = 3 × 2= 6 inch²

Area = l × h

Area = 6 × 2 = 12 inch²

Now we have to calculate the volume of solid.

volume of solid = l × b × h

volume of solid = 6 × 3 × 2

volume of solid = 36 inches³

The volume of solid is, 36 inches³

Answer 2

Answer:

Step-by-step explanation:

The solid is a cuboid with length of 6 inches, a width of 3 inches, and a height of 2 inches.

The volume is l× w×h = 6×3×2 = 36inches^3

Therefore, the following statements are true about the Solid

1) The volume of the solid is 36 in.3.

2) The perimeter of one of its faces is 10 inches.(2width + 2 height = 2×2 + 2×3 = 10 inches)

3) The area of one of its faces is 6 inches^2. (width × height = 3×2 = 6 inches)

4) The area of one of its faces is 12 in.2.(length × height = 6×2 = 12 inches^2)