3 years ago

What is the solution of StartRoot x + 12 EndRoot = x?

Mathematics

2 answers:

Dmitriy789 [7]3 years ago

8 0

Answer:

B) x=4

Step-by-step explanation:

I just got a 100% on the unit test from EDGE.

Ber [7]3 years ago

4 0

Answer:

x = 4 or x = -3

Step-by-step explanation:

$\sqrt{x+12}=x$

Take square both the sides,

$(\sqrt{x+12})^{2}=x^{2}\\\\x+12=x^{2}$

x² - x - 12 = 0

x² - 4x + 3x - 3*4 =0

x*(x - 4) + 3*(x - 4)= 0

(x- 4 )(x+3) =0

x -4 =0 or x + 3 = 0

x = 4 or x = -3

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