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NeTakaya
3 years ago
10

Can you help me with this ?

Mathematics
1 answer:
Artist 52 [7]3 years ago
8 0
I believe the answer is 24
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Please answer correctly !!!!!! Will mark brainliest answer !!!!!!!!!!
Rasek [7]

Answer:

see below

Step-by-step explanation:

1. 0 = (r + 1)(r + 8)

Using Zero Product Property, r = -1, r = -8

2. h(r) = (r + 1)(r + 8)

         = r² + 9r + 8

         = (r + 9/2)² - 81/4 + 8

         = (r + 4.5)² - 12.25 (Complete the square)

   Vertex: (-4.5, -12.25)

5 0
3 years ago
Helpppppppppppppppppppppppp
guajiro [1.7K]
The anwser is c your welcome
4 0
3 years ago
Read 2 more answers
What is the approximate length of the apothem? 0. 4 cm 0. 8 cm 1. 5 cm 1. 9 cm.
arsen [322]

The length of apothem for a regular hexagon with radius of 18 cm and side of 18 cm is 15.6 cm

<h3>What is apothem?</h3>

The apothem of a regular polygon is a line segment from the center to the midpoint of one of its sides.

Let a represent the length of the apothem. Hence half of the side = 18/2 = 9 cm.

Using Pythagoras:

18² = a² + 9²

The length of apothem for a regular hexagon with radius of 18 cm and side of 18 cm is 15.6 cm

Find out more on apothem at: brainly.com/question/369332

7 0
2 years ago
What is the zero of y=-4x^2+8x-28
tangare [24]

Solution, y-4x^2+8x-28=0:\quad \mathrm{Parabola\:with\:vertex\:at}\:\left(h,\:k\right)=\left(1,\:24\right),\:\mathrm{and\:focal\:length}\:|p|=\frac{1}{16}

Steps:

\mathrm{Rewrite}\:y-4x^2+8x-28=0\:\mathrm{in\:the\:standard\:form}

\mathrm{Rewrite\:as}, y=4x^2-8x+28

\mathrm{Complete\:the\:square}\:4x^2-8x+28:\quad 4\left(x-1\right)^2+24, y=4\left(x-1\right)^2+24

\mathrm{Subtract\:}24\mathrm{\:from\:both\:sides}, y-24=4\left(x-1\right)^2

\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4, \frac{1}{4}\left(y-24\right)=\left(x-1\right)^2

\mathrm{Rewrite\:in\:standard\:form}, 4\cdot \frac{1}{16}\left(y-24\right)=\left(x-1\right)^2

\mathrm{Therefore\:parabola\:properties\:are:} \left(h,\:k\right)=\left(1,\:24\right),\:p=\frac{1}{16}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-\:austint1414}

8 0
3 years ago
Square OPQR is inscribed in triangle ABC. The areas of △AOR, △BOP, △CRQ are 1, 3, and 1, respectively. What is the area of squar
FromTheMoon [43]

Answer:

9 units²

Step-by-step explanation:

We know that ΔCRQ and ΔBOP are right triangles because RQ and OP are perpendicular to CB.

ΔAOR must also be a right triangle because ∠AOR = ∠OBP and ∠ARO = ∠RCQ.

Because of the Angle-Angle-Angle theorem, we know that ΔAOR ≅ ΔBOP ≅ ΔCRQ.

AR/AO = OP/PB

3(1/2)(AR)(AO) = (1/2)(OP)(PB)

PB = 6, OP = 3

3 x 3 = 9 units²

7 0
3 years ago
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