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3 years ago

Y = 5.7x + 14.34 y= - 2x - 2.6

Mathematics

1 answer:

ladessa [460]3 years ago

6 0

Step-by-step explanation:

what is it asking you to do

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4 years ago

What value of n will make the equation true ?

kompoz [17]

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Step-by-step explanation:

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3 years ago

HELPP ITS 6 GRADE MATHS LOLLLL

Citrus2011 [14]

Answer:

-4

Step-by-step explanation:

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3 years ago

Read 2 more answers

Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.

mart [117]

Answer:

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

Step-by-step explanation:

The given expression is

$\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}$

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

$\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}$ $[\because a^ma^n=a^{m+n}]$

$\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}$

$\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}$ $[\because a^{-n}=\dfrac{1}{a^n}]$

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is $\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

5 0

4 years ago

3x + 4y = 2<br> 2x + 4y =8

BabaBlast [244]

We see that both equations have 4y in them. Subtracting the second equation from the first equation, we get (3x -2x) + (4y-4y) = 2 - 8, x = -6

Plugging x = -6 into any equation, we see that our answer is 18 + 4y = 2, 4y = 2 - 18 = -16, y = -4.

Our answer is x = -6, y = -4

5 0

4 years ago