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BlackZzzverrR [31]
3 years ago
12

A teacher decides to purchase a new car and considers two options. Option one is the new Zoomba for $60,000 with an expected dep

reciation of 2% per month. Option two is the new Starfish for $40,000 with an expected depreciation of $200 per month. The teacher plans to keep the car for three years and chooses the option that is expected to retain the most value. Which option did the teacher choose (exponential or linear), and what was the value of the chosen option after three years? A) The teacher chose the linear option with an expected value of $32,800. B) The teacher chose the linear option with an expected value of $28,992.79. C) The teacher chose the exponential option with an expected value of $32,800. D) The teacher chose the exponential option with an expected value of $28,992.79.
Mathematics
1 answer:
Igoryamba3 years ago
8 0
Don’t now the answer but 60000 2% would be 1200 times 12 time 3 would be 43200$ for the 60k one and then 200 a month would be 7200 for three years that’s all I know
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Consider the following sets: R = {x | x is the set of rectangles} P = {x | x is the set of parallelograms} T = {x | x is the set
Liula [17]
"T is a subset of P"

Not true since triangle has three sides but parallelogram has four sides.

"E is a subset of I"

True since equilateral triangles are isosceles triangles with all angles equal.

"S is a subset of T"

True since scalene triangles are still triangle.

"I ⊂ E"

False since there are isosceles triangles those are not equilateral triangles. Namely triangle with angles 20°, 20°, 140°

"T ⊂ E"

False since not all triangles are equilateral. Scalene triangle is one of counterexamples.

"R ⊂ P"

True since rectangles are parallelograms with right angles.

Final answer: <span>E is a subset of I, </span>S is a subset of T, and R ⊂ P.

Hope this helps.
6 0
3 years ago
Read 2 more answers
A 75-gallon tank is filled with brine (water nearly saturated with salt; used as a preservative) holding 11 pounds of salt in so
Debora [2.8K]

Let A(t) = amount of salt (in pounds) in the tank at time t (in minutes). Then A(0) = 11.

Salt flows in at a rate

\left(0.6\dfrac{\rm lb}{\rm gal}\right) \left(3\dfrac{\rm gal}{\rm min}\right) = \dfrac95 \dfrac{\rm lb}{\rm min}

and flows out at a rate

\left(\dfrac{A(t)\,\rm lb}{75\,\rm gal + \left(3\frac{\rm gal}{\rm min} - 3.25\frac{\rm gal}{\rm min}\right)t}\right) \left(3.25\dfrac{\rm gal}{\rm min}\right) = \dfrac{13A(t)}{300-t} \dfrac{\rm lb}{\rm min}

where 4 quarts = 1 gallon so 13 quarts = 3.25 gallon.

Then the net rate of salt flow is given by the differential equation

\dfrac{dA}{dt} = \dfrac95 - \dfrac{13A}{300-t}

which I'll solve with the integrating factor method.

\dfrac{dA}{dt} + \dfrac{13}{300-t} A = \dfrac95

-\dfrac1{(300-t)^{13}} \dfrac{dA}{dt} - \dfrac{13}{(300-t)^{14}} A = -\dfrac9{5(300-t)^{13}}

\dfrac d{dt} \left(-\dfrac1{(300-t)^{13}} A\right) = -\dfrac9{5(300-t)^{13}}

Integrate both sides. By the fundamental theorem of calculus,

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac1{(300-t)^{13}} A\bigg|_{t=0} - \frac95 \int_0^t \frac{du}{(300-u)^{13}}

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac{11}{300^{13}} - \frac95 \times \dfrac1{12} \left(\frac1{(300-t)^{12}} - \frac1{300^{12}}\right)

\displaystyle -\dfrac1{(300-t)^{13}} A = \dfrac{34}{300^{13}} - \frac3{20}\frac1{(300-t)^{12}}

\displaystyle A = \frac3{20} (300-t) - \dfrac{34}{300^{13}}(300-t)^{13}

\displaystyle A = 45 \left(1 - \frac t{300}\right) - 34 \left(1 - \frac t{300}\right)^{13}

After 1 hour = 60 minutes, the tank will contain

A(60) = 45 \left(1 - \dfrac {60}{300}\right) - 34 \left(1 - \dfrac {60}{300}\right)^{13} = 45\left(\dfrac45\right) - 34 \left(\dfrac45\right)^{13} \approx 34.131

pounds of salt.

7 0
2 years ago
A rectangular prism has a volume of 729 ft3. The length width and height are all the same. What is the is the length of each sid
swat32

Answer:

9 ft

Step-by-step explanation:

As length, width and height are same, then it is a square prism / cube

Volume of prism = 729 ft³

side³ = 729

side³ = 9³

Side = 9 ft

3 0
3 years ago
Read 2 more answers
Eureka math lesson 5 5.3
dangina [55]

A is 1/12.

B is 1/6.

C is 7/12.

D is 11/21


3 0
3 years ago
Read 2 more answers
PLEASE HELP!!
aliya0001 [1]

Ik this is late, but people who are looking for the answer can see this.

Answer:

an =1/3*6^n-1

Step-by-step explanation:

You should plug in 2 for n in each equation, which, the correct one should give you 2. Then, to make sure, you plug in 3 in the equations that gave you 2.

Example:

an = 1/3 * 6 ^n-1

Plug in 2.

an = 1/3 * 6 ^2-1

an = 1/3 * 6 ^1

1/3 * 6 = 2

Step 2.

an = 1/3 * 6 ^3-1

an = 1/3 * 6 ^2

1/3 * 36 = 12

Hope this helps.

4 0
3 years ago
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