Answer:
; 
Step-by-step explanation:
I have never done a problem like this, so this is my first time attempting it.
The standard form for the equation of a circle is:

Begin by grouping the 'x' terms and 'y' terms:

Complete the square for the second polynomial:





Do the exact same process with the other polynomial:

Complete the square:





Bring the 121 to the other side to get:


The above expression is the equation of our circle in standard form. It is centered at the coordinates (7, -2) and has a radius of 11 units. The area of a circle if given by:

Answer:
3.5.
Step-by-step explanation:
3^2 = 9
and 4^2 = 16 so the square root is between 3 and 4.
Take a rectangle 3.4 by 3.6:
the area = 3.4 * 3.6 = 12.24 so an estimate of the square root could be 3.5.
3.5 * 3.5 = 12.25.
Answer:
3cm
Step-by-step explanation:
A parallelogram is quadrilateral that has two pairs of parallel sides. The opposite sides equal in length
Area of a parallelogram = base x height
18cm² = 6cm x height
height = 18cm² / 6cm = 3cm
Answer:
Not possible to work out
Step-by-step explanation:
NO Explanation can be explained as this question cannot be solved
The intercepts are -2 and -7 on the x-axis