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balandron [24]
3 years ago
8

The zeros to the equation 3 x 2 − 5 x − 2 = 0 are x = 3 and x = 2.

Mathematics
1 answer:
Sati [7]3 years ago
8 0

Answer:

False

Step-by-step explanation:

Solving the equation

3x² - 5x - 2 = 0

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 3 × - 2 = - 6 and sum = - 5

The factors are - 6 and + 1

Use these factors to split the x- term

3x² - 6x + x - 2 = 0 ( factor the first/second and third/fourth terms )

3x(x - 2) + 1(x - 2) = 0 ← factor out (x - 2) from each term

(x - 2)(3x + 1) = 0

Equate each factor to zero and solve for x

x - 2 = 0 ⇒ x = 2

3x + 1 = 0 ⇒ 3x = - 1 ⇒ x = - \frac{1}{3}

Solutions are x = 2 and x = - \frac{1}{3}

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The graph of a quadratic function passes through the points (-1,0), (-2,0), and (0,2). Write the quadratic function in general f
ddd [48]

Answer:

f(x)=x^2+3x+2

Step-by-step explanation:

step 1

we have the points

(-1,0), (-2,0), and (0,2)

Plot the points

using a graphing tool

see the attached figure

The graph of a quadratic function must be a vertical parabola open upward

The vertex is a minimum

The quadratic function in general form is equal to

f(x)=ax^2+bx+c

Substitute the value of x and the value of y of each given ordered pair in the general equation and solve for a,b and c

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For x=0, y=2

substitute

2=a(0)^2+b(0)+c

c=2

(-1,0)

For x=-1, y=0

substitute

0=a(-1)^2+b(-1)+2

0=a-b+2 ----> a=b-2 ----> equation A

(-2,0)

For x=-2, y=0

substitute

0=a(-2)^2+b(-2)+2

0=4a-2b+2 ----> equation B

we have the system

a=b-2 ----> equation A

0=4a-2b+2 ----> equation B

substitute equation A in equation B

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solve for b

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Find the value of a

a=3-2=1

therefore

The quadratic function in general form is equal to

f(x)=x^2+3x+2

see the attached figure N 2 to better understand the problem

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