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brilliants [131]
3 years ago
8

Find the number of real number solutions for the equation. x2 – 10x + 25 = 0 2 1

Mathematics
1 answer:
Makovka662 [10]3 years ago
5 0
1.........................
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2 years ago
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A. x = 2, y =6<br> B. x = 2, y =3<br> C. x =-2, y =3<br> D. x = -3, y =2
AlekseyPX

Answer:

The correct answer is A) x = 2 and y = 6

Step-by-step explanation:

In order to find the answer, we need to set the hypotenuses equal to each other. Then we can solve for y to get the equation.

y - 1 = x + 3

y = x + 4

Now we can do the same with the leg lengths.

y - 3 = 2x - 1

y = 2x + 2

Now that we have two equations, we can set them equal to each other to get the x value.

x + 4 = 2x + 2

4 = x + 2

2 = x

Now that we have x, we can plug it into any equation to get the y value.

y = x + 4

y = 2 + 4

y = 6

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3 years ago
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Use the distributive property to fill in the blanks below.
elena-14-01-66 [18.8K]

Answer:

(5×7)-(5×6) = 5×(7-6)

5 0
3 years ago
Which function rule describes the number of centimeters y as a function of a number of millimeters x?
ira [324]
Y= 10x
y: number of cm
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7 0
3 years ago
The amount that two groups of students spent on snacks in one day is shown in the dot plots below. Which statements about the me
RUDIKE [14]

Answer:

  • The mean for Group A is less than the mean for Group B.
  • The median for Group A is less than the median for Group B.
  • The mode for Group A is less than the mode for Group B.

Step-by-step explanation:

First, we can find the measures of center for each group.

<u>Group A</u>

Mode: 1

Median: (1 + 2) / 2 = 3 / 2 = 1.5

Mean: (1 * 5 + 2 * 4 + 3) / 10 = (5 + 8 + 3) / 10 = 16 / 10 = 1.6

<u>Group B</u>

Mode: 3

Median: 92 + 3) / 2 = 5 / 2 = 2.5

Mean: (1 * 3 + 2 * 2 + 3 * 4 + 5) / 10 = (3 + 4 + 12 + 5) / 10 = 24 / 10 = 2.4

From here, we can see that...

  • The mean for Group A is less than the mean for Group B.
  • The median for Group A is less than the median for Group B.
  • The mode for Group A is less than the mode for Group B.

Hope this helps!

8 0
3 years ago
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