6x^2 + 4(x^2 - 1) =
6x^2 + 4x^2 - 4 =
10x^2 - 4 <===
Answer:
(x-6)^2+(y-14)^2=4
Step-by-step explanation:
Answer:
2+2=4-1=3 quick mafs everyday mans on da block, smoke trees
For this case, the first thing we must do is define variables:
x = number of quarters
y = number of dimes
We now write the system of equations:
x + y = 28
0.25x + 0.10y = 4.05
Solving the system of equations we have:
x = 8.33
y = 19.66
Rounding:
x = 8
y = 20
Answer:
the college student has:
8 quarters
20 dimes
