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inn [45]
3 years ago
13

i need to find the area of a rectangle using the formula A=b*h the height is 810 cm the base is 10 meters...i know i need to con

vert, but how do i set up the equation to gigute/work this this out?​
Mathematics
1 answer:
leva [86]3 years ago
7 0

Answer:

81000cm^{2}  or   8.1m^{2}

Step-by-step explanation:

1m = 100cm

10m = 1000cm

a= b*h

a= 1000cm * 810cm

= 810000cm^{2}

1m^{2} = 10000cm^{2}

810000cm^{2} = 8.1m^{2}

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1/3

Step-by-step explanation:

Y/x=k that is the equation for constant of proportionality

2/6=k

1/3=k

5 0
3 years ago
Need help will give Brain latest
Brums [2.3K]

Answer:

6%

Step-by-step explanation:

Using the formula I=PRT we have 96.12=(267)R(6). we simplify the right by doing the multiplication 267x6 so we have 96.12=1602R. again using algebra we divide both sides by 1602 to isolate R. we get R=0.06 and when converted to a percent is 6%.

6 0
3 years ago
C-c+a+ |a|; use a = 4, and c=5
Ulleksa [173]

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Step-by-step explanation:

5 0
3 years ago
Winston owns a coffee cart. He charges $3.50 for a cup of coffee, and it costs him $1.50 to make each cup of coffee plus $100 a
jekas [21]

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50 cups of coffee

Step-by-step explanation:

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6 0
3 years ago
Calculate the axis of symmetry in the equation Y = (x+1) (x-4)
algol [13]

Answer:

<em>Every </em><em>parabola </em><em>has </em><em>a </em><em>turning</em><em> point</em><em> </em><em>called </em><em>the </em><em>axis</em><em> of</em><em> symmetry</em><em>,</em><em>so </em><em>for </em><em>this </em><em>question</em><em> </em><em>you </em><em>just</em><em> </em><em>have </em><em>to </em><em>find </em><em>the </em><em>turning</em><em> </em><em>points</em>

<em>x </em><em>turning</em><em> </em><em>point</em><em>=</em><em> </em><em>-b/</em><em>2</em><em>a</em><em>,</em><em>and </em><em>the </em><em>y </em><em>turning</em><em> </em><em>point</em><em> </em><em>is </em><em>gotten</em><em> </em><em>by </em><em>replacing</em><em> </em><em>the </em><em>value </em><em>of </em><em>x </em><em>in </em><em>the </em><em>equation</em>

<em>y=</em><em>(</em><em>x+</em><em>1</em><em>)</em><em>(</em><em>x-4)</em>

<em> </em><em> </em><em>=</em><em>x^</em><em>2</em><em>-</em><em>3</em><em>x</em><em>-</em><em>4</em>

<em>a </em><em>is </em><em>1</em><em>,</em><em>b </em><em>is </em><em>-</em><em>3</em><em> </em><em>and </em><em>c </em><em>is </em><em>-</em><em>4</em>

<em>x=</em><em> </em><em>-</em><em>(</em><em>-</em><em>3</em><em>)</em><em>/</em><em>2</em><em>(</em><em>1</em><em>)</em>

<em> </em><em> </em><em>=</em><em>1</em><em>.</em><em>5</em>

<em>and </em><em>y=</em><em>x^</em><em>2</em><em>-</em><em>3</em><em>x</em><em>-</em><em>4</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>1</em><em>.</em><em>5</em><em>^</em><em>2</em><em>-</em><em>3</em><em>(</em><em>1</em><em>.</em><em>5</em><em>)</em><em>-</em><em>4</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>-</em><em>6</em><em>.</em><em>2</em><em>5</em>

<em>therefore</em><em> </em><em>the </em><em>axis </em><em>of</em><em> symmetry</em><em> is</em><em> (</em><em>1</em><em>.</em><em>5</em><em>,</em><em>-</em><em>6</em><em>.</em><em>2</em><em>5</em><em>)</em>

<em>I </em><em>hope </em><em>this </em><em>helps</em>

6 0
3 years ago
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