News Report.
I hope this helps! :)
Explanation:
What code are you talking about?
Answer:
su ,sg and sudo command.
Explanation:
Whenever the user needs to enable workgroup mates should use fdisk including just that disk on both the /dev / sda disk, using the following command to update and configure the following packages. Thus he uses the command su, sg, and sudo.
So, the following commands are required according to the following statement.
The software is written in C++ and may be found in the explanation section below. C++ keywords and symbols are all capitalized. The least number of all three integers is determined via a nested if-else decision branch. After you've entered three integers, the application prints the least of them all.
<h3>
What is the example of C++?</h3>
#include <iostream>
using namespace std;
int main() {
int num1,num2,num3;
cout<<"enter first integers"<<endl;
cin>>num1;
cout<<"enter second integers"<<endl;
cin>>num2;
cout<<"enter the third integers"<<endl;
cin>>num3;
if(num1<num2){
if(num1<num3){
cout<<"Smallest integer is "<<num1<<endl;
} else{
cout<<"Smallest integer is "<<num3<<endl;
}
}else {
if(num2<num3){
cout<<"Smallest integer is "<<num2<<endl;
} else{
cout<<"Smallest integer is "<<num3<<endl;
}
}
return 0;
}
Thus, it is written in C++ language.
For more details about C++ click here:
brainly.com/question/19581899
#SPJ1
Answer:
(a)The CPU B should be selected for the new computer as it has a low clock cycle time which implies that it will implement the process or quicker when compared to the CPU A.
(b) The CPU B is faster because it executes the same number of instruction in a lesser time than the CPU A
.
Explanation:
Solution
(a)With regards to the MIPS performance metric the CPU B should be chosen for the new computer as it low clock cycle time which implies that it will implement the process or quicker when compared to the CPU A and when we look at the amount of process done by the system , the CPU B is faster when compared to other CPU and carries out same number of instruction in time.
The metric of response time for CPU B is lower than the CPU A and it has advantage over the other CPU and it has better amount as compared to CPU A, as CPU B is carrying out more execution is particular amount of time.
(b) The execution can be computed as follows:
Clock cycles taken for a program to finish * increased by the clock cycle time = the Clock cycles for a program * Clock cycle time
Thus
CPU A= 5*10^6 * 60*10^-9 →300*10^-3 →0.3 second (1 nano seconds =10^-9 second)
CPU B= 3 *10^6 * 75*10^-9 → 225*10^-3 → 0.225 second
Therefore,The CPU B is faster as it is executing the same number of instruction in a lesser time than the CPU A