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nikklg [1K]
3 years ago
6

Can someone help with this plz

Mathematics
1 answer:
LekaFEV [45]3 years ago
6 0

Answer:

  • divide
  • multiple
  • multiple
  • multiple
  • divide
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Find the median, first quartile, third quartile, and interquartile range of the data.
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Answer:

Median: 55

First quartile: 26.5

Third quartile: 93

Interquartile range: 66.5

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Fill in the missing number in this sequence:<br> { } 216, 36, 6, 1
schepotkina [342]

Answer:

1296

Step-by-step explanation:

times each number by 6

example: 1x6=6 6x6=36 36x6=216 216x6=1296

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a triangle has a perimeter of 10x+2 . two sides have lengths of 5x and 2x+9 what is the length of the 3rd side
stiks02 [169]
Since all the sides add up to 10x+2, that means that 10x-2-<side1>-<side2>=<side3>. Plugging it in, we have 10x-2-5x-(2x+9)=side3, and 5x-2-(2x+9)=side3, then expanding it to 5x-2-2x-9=3x-11=side3
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3 years ago
40,583 in word format .......................................................... ......... .........
lozanna [386]
Forty-thousand, five-hundred eighty-three.
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3 years ago
The table shows the results of an experiment in which subjects taking either a drug or a placebo either reported fatigue or did
Lady bird [3.3K]

Answer:

Therefore, the correct options are;

-P(fatigue) = 0.44

P(fatigue \left |  \right drug) = 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Step-by-step explanation:

Here we have that for dependent events,

P(A \, and \, B)= P(A)\times  P(B\left |  \right A )

From the options, we have;

P(fatigue \left |  \right drug) = 0.533

P(drug) = 0.6

P(drug and fatigue) = 0.32

Therefore

P(drug and fatigue) = P(drug)×P(fatigue \left |  \right drug)  

= 0.6 × 0.533 = 0.3198 ≈ 0.32 = P(drug and fatigue)

Therefore, the correct options are;

-P(fatigue) = 0.44

P(fatigue \left |  \right drug) = 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Since P(fatigue) = 0.44 ∴ P(drug) = 0.264/0.44 = 0.6.

4 0
3 years ago
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