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Kryger [21]
3 years ago
15

Use the Quadratic Formula to solve x2 + 20x + 98 = 0

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
3 0
ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\if\ \Delta \ \textless \  0\ then\ no\ solution\\\\if\ \Delta =0\ then\ one\ solution\ x_0=\dfrac{-b}{2a}\\\\if\ \Delta \ \textgreater \  0\ then\ two\ solutions\ x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\-----------------------------

x^2+20x+98=0\\a=1;\ b=20;\ c=98\\\\\Delta=20^2-4\cdot1\cdot98=400-392=8 \ \textgreater \  0\\\sqrt\Delta=\sqrt8=\sqrt{4\cdot2}=\sqrt4\cdot\sqrt2=2\sqrt2\\\\x_1=\dfrac{-20-2\sqrt2}{2\cdot1}=\dfrac{-20-2\sqrt2}{2}=-10-\sqrt2\\\\x_2=\dfrac{-20+2\sqrt2}{2\cdot1}=\dfrac{-20+2\sqrt2}{2}=-10+\sqrt2
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PART1
Mice21 [21]
Part 1:\frac{5x^{3} + 10x^{2} + 15x}{5x} = \frac{5x^{3}}{5x} + \frac{10x^{2}}{5x} + \frac{15x}{5x} = x^{2} + 2x + 3
The answer is C.

Part 2:\frac{3x^{4} + 5x^{2} + 2x}{x} = \frac{3x^{4}}{x} + \frac{5x^{2}}{x} + \frac{2x}{x} = 3x^{3} + 5x + 2
The answer is A.
8 0
3 years ago
50% of what number is 11.72
Setler [38]

Answer:

50% of what number is 11.72 = 23.44

Step-by-step explanation:

50% is half, so simply doube it.

5 0
3 years ago
In this line of circles, the ratio of red circles to blue circles is 1:3 How many more circles would need to be added to make th
zaharov [31]

Answer:

The number of red circles to be added would be equal to 8 times the original amount of red circles

Step-by-step explanation:

Let

x ----> the number of red circles

y ----> the number of blue circles

Originally

\frac{x}{y}=\frac{1}{3}

y=3x ----> equation A

How many more circles would need to be added to make the ratio of red to blue 3:1

Let

n ----> the  number of additional red circles

\frac{x+n}{y}=\frac{3}{1} ----> equation B

substitute equation A in equation B

\frac{x+n}{3x}=\frac{3}{1}

solve for n

x+n=9x\\n=9x-x\\n=8x

therefore

The number of red circles to be added would be equal to 8 times the original amount of red circles

5 0
3 years ago
Whats 10 divided by 489
Jobisdone [24]

Answer:

0.02044989775

Step-by-step explanation:

5 0
3 years ago
For each pair of triangles,tell:(a) are they congruent(b)write the triangle congruency statement.(c) Give the postulate that mak
pychu [463]
All right...before we begin, let's lay some ground rules about the postulate your teacher asks for in every problem. <em>If you already know what they are, skip this paragraph...</em>

A postulate is a statement that claims how the triangles are congruent from looking at the paper. For example, on number 2 we have three sides of the triangle so we would use the postulate SSS (side, side, side). However, number one we would use SAS (side, angle, side) because we see the angle square showing it is a 90-degree angle.
Let's begin! (I haven't done triangles in a while so I apologize in advance if some of my answers might be incorrect on the congruent (yes or no) part of it.)

1.
A) From a visual perspective, we can see the triangles are congruent.
B) ABE = CDE because they are the corresponding points.
C) We can use SAS for the postulate.

2.
A) Yes, they are congruent.
B) OLE = OVE
C) We can use SSS for their postulate.

3.
A) Yes, they are congruent.
B) AWT = ERT
C) We can use SAS for the postulate.

4.
A) I believe the triangles are congruent. You might want to check me on that.
B) GFE = FGH
C) SSS

5.
A) They are congruent because if IH bisects it, it is directly in the middle. So, we know that WH = HS and IH = IH (duh.) and their angles match.
B) WHI = SHI
C) SAS

6.
A) This one is intriguing because it would state above the shape "LE bisects LGUE." I'm going to take that it isn't exactly in the middle, but I am still going to say it is congruent.
B) LGE = EUL
C) ASA

7.
A) Yes, they are definitely congruent.
B) RTU = TRS
C) SSS (We have nothing that indicates angles.)

8.
A) Yes, they are congruent.
B) YWV = VZY
C) We can use SAS. (Might want to check that one.)

9.
A) I would say this one is NOT congruent.
B) There are only two points. One way is HT = MA
C) They are not congruent, you can not use a postulate. However, if you teacher insists on putting one, I would use SAS.

Once again, I would be careful about my answers. I haven't worked with triangles in a few years. If my math is incorrect, or I didn't give the answer you were looking for, please let me know. However, if my math is on point, please consider marking as <em>Brainliest</em>.

Have a good one.
God Bless.
7 0
3 years ago
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