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Licemer1 [7]
3 years ago
6

Name two lines in the diagram.

Mathematics
1 answer:
Oksanka [162]3 years ago
6 0

Answer:

Options (3) and (6)

Step-by-step explanation:

"A straight line is a set of all points between two points and extending beyond these points."

Therefore, from the given diagram,

Arrows connecting set of two points B and C and D and E will be straight lines.

Geometrically we denote them with an arrow over the line.

\overleftrightarrow {BC} and \overleftrightarrow {DE}

Therefore, Options (3) and (6) will be the answer.

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the specification for a plastic handle calls for a length of 6.0 inches +- .2 inches. The standard deviation of the process is e
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Answer:

a)

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c)

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Step-by-step explanation:

The specification for a plastic handle calls for a length of 6.0 inches ± .2 inches. The standard deviation of the process is estimated to be 0.05 inches. What are the upper and lower specification limits for this product? The process is known to operate at a mean thickness of 6.1 inches. What is the Cp and Cpk for this process?   Is this process capable of producing the desired part?

Given that:

Mean (μ) = 6.1 inches, Standard deviation (σ) = 0.05 inches and the length of the plastic handle is 6.0 inches ± .2

a) Since the length of the plastic handle is 6.0 inches ± .2  = (6 - 0.2, 6 + 0.2)

The Upper specification limits (USL) = 6 inches + 0.2 inches = 6.2 inches

The lower specification limits (LSL) = 6 inches - 0.2 inches = 5.8 inches

b) The Cp is given by the formula:

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The Cpk is given by the formula:

c)

The upper specification limit lies about 3 standard deviations from the centerline, and the lower specification limit is further away, so practically all units will meet specifications

Cpk=min(\frac{USL-\mu}{3\sigma},\frac{\mu -LSL}{3\sigma})=min(\frac{6.2-6.1}{3*0.05},\frac{6.1-5.8}{3*0.05})=min(0.67,2)=0.67

7 0
3 years ago
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How do I solve these trigonometric functions?
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Answer:

see attached

Step-by-step explanation:

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