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SpyIntel [72]
3 years ago
7

Three fifths of the cast in a musical have to sing.What fraction on the cast does not have to sing?

Mathematics
2 answers:
notka56 [123]3 years ago
7 0
The term "three fifths" is equivalent to \frac{3}{5}.
If \frac{3}{5} of the cast is singing, then we just have to find the rest of the fraction.
1- \frac{3}{5} \\  \frac{5}{5}- \frac{3}{5}    \\  \frac{2}{5}
cricket20 [7]3 years ago
6 0
Well, 3/5 of the cast is singing and the whole group would be 5/5 so then that makes 5/5 minus 3/5 which equals <em><u>2/5</u></em> don't have to sing!
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A grocery stores studies how long it takes customers to get through the speed check lane. They assume that if it takes more than
Lemur [1.5K]

Answer:

4.65% probability that a randomly selected customer takes more than 10 minutes

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 7.45, \sigma = 1.52

Probability that a customer takes more than 10 minutes:

This is 1 subtracted by the pvalue of Z when X = 10. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{10 - 7.45}{1.52}

Z = 1.68

Z = 1.68 has a pvalue of 0.9535

1 - 0.9535 = 0.0465

4.65% probability that a randomly selected customer takes more than 10 minutes

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3 years ago
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Paha777 [63]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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