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4 years ago

What is the equation of a circle with center (-7, -3) and radius 2?

Mathematics

1 answer:

amid [387]4 years ago

3 0

Answer:

B = (x + 7)^2 + (y +3)^2 = 4

Step-by-step explanation:

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Write an expression for each quantity

Ira Lisetskai [31]

28) 7w
30) x/16
32) I/12

4 0

4 years ago

5x-0.1=4x I need to know what X is not sure how to solve

masha68 [24]

<span>5x-0.1=4x
Subtract 5x from both sides so that the x variable is only on one side
-0.1=-x
Divide both sides by -1 to get rid of the negative on the side with the x variable
Final Answer: 0.1=x</span>

8 0

4 years ago

Read 2 more answers

Factor completely: 4v^4-6v^3-10v^2. i factored and got 2v^2(v^2-3v-5). can i go further?

lisov135 [29]

Yes you can go further, also replacing V with X)
x^2-3x-5
(x+2)(x-3)

8 0

3 years ago

What is the midpoint of the segment of the segment that would be created between points L and N on a graph?

il63 [147K]

Option A:

Midpoint of LN = (2, 3)

Solution:

In the given graph we can find the coordinates of L and N.

Coordinates of L = (–2, 3)

Coordinates of N = (6, 3)

Here, $x_{1}=-2, x_{2}=6, y_{1}=3, y_{2}=3$

Let us find the midpoint of the segment LN.

<u>Midpoint formula:</u>

$$\text { Midpoint }=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

$\begin{aligned}&=\left(\frac{-2+6}{2}, \frac{3+3}{2}\right)\\&=\left(\frac{4}{2}, \frac{6}{2}\right)\\&=(2,3)\end{aligned}$

Midpoint of LN = (2, 3)

Option A is the correct answer.

Hence the coordinates of the midpoint of the line segment LN is (2, 3).

6 0

3 years ago

ANSWER ASAP PLZ!!

Vikentia [17]

$\text{If is}\\\\\left\{\begin{array}{ccc}0.2-0.3y=4\\2.3x-y=1.2\end{array}$

Answer:

$\large\boxed{\left(-\dfrac{344}{69},\ -\dfrac{38}{3}\right)}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}0.2-0.3y=4\\2.3x-y=1.2&\text{multiply both sides by (-0.3)}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}0.2-0.3y=4\\-0.69x+0.3y=-0.36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad-0.69x+0.2=3.64\qquad\text{subtract 0.2 from both sides}\\.\qquad-0.69x=3.44\qquad\text{divide both sides by (-0.69)}\\.\qquad x=-\dfrac{3.44\cdot100}{0.69\cdot100}\\.\qquad \boxed{x=-\dfrac{344}{69}}\\\\\text{Calculate the value of y from first equation:}$

$0.2-0.3y=4\qquad\text{subtract 0.2 from both sides}\\-0.3y=3.8\qquad\text{divide both sides by (-0.3)}\\y=-\dfrac{3.8\cdot10}{0.3\cdot10}\\\boxed{y=-\dfrac{38}{3}}$

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$\text{If is}\\\\\left\{\begin{array}{ccc}0,2x-0,3y=4\\2.3x-y=1.2\end{array}\right$

Answer:

$\large\boxed{\left(-\dfrac{52}{7},\ -\dfrac{128}{7}\right)}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}0.2x-0.3y=4&\text{multiply both sides by 10}\\2.3x-y=1.2&\text{multiply both sides by 10}\end{array}\right\\\\\left\{\begin{array}{ccc}2x-3y=40&\text{multiply both sides by (-10)}\\23x-10y=12&\text{multiply both sides by 3}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-20x+30y=-400\\69x-30y=36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad49x=-364\qquad\text{divide both sides by 49}\\x=-\dfrac{364:7}{49:7}\\.\qquad\boxed{x=-\dfrac{52}{7}}$

$2\left(-\dfrac{52}{7}\right)-3y=40\\-\dfrac{104}{7}-3y=40\qquad\text{multiply both sides by 7}\\-104-21y=280\qquad\text{add 104 to both sides}\\-21y=384\qquad\text{divide both sides by (-21)}\\y=-\dfrac{384:3}{21:3}\\\boxed{y=-\dfrac{128}{7}}$

7 0

4 years ago