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3 years ago

The cost of 12 oranges and 7 coples is 55.36. Eight oranges and apples cost $3.68. Find the cost

1 answer:

4 0

Hello there i hope you are having a good day :) Your question : The cost of 12 oranges and 7 couples is 55.36. Eight oranges and apples cost $3.68. Find the cost of each : Firstly you would do oranges = O Apples = A. Then 12 oranges + 7 apples = 5.36 12o + 7A = 5.36 then you would take away from both sides so -12o Take away -12o = 7o = 5.36 - 12A now you would divide this by 7 so 7 cancels each out so you are left with 5.36/ 7 = 0.76 Then it would equal 0.76 - 12o/7 This would equal the amount of apples to be $0.76 each now for the oranges you would do the same that you work out for the apples.

Hopefully that help ya :)

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Svetllana [295]

Explanation:

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1) For x-intercept, y will be 0

(x-4)(x+2) = 0

(x-4) =0, (x+2) = 0

x = 4, x = -2

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2 years ago

Read 2 more answers

Find the x intercept. (Using the equation is more accurate, but I included a graph for reference)

MariettaO [177]

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As the marbles are identical, we do not really care for permutations (as we can really not difference them)

If we have 5 blue marbles, we have only one combination.

B-B-B-B-B

If we have 4 blue marbles, we have 3 combinations:

B-B-B-B-G, G-B-B-B-B, B-B-G-B-B

This is because the blue marbles need to be next to another blue one, so from here we can do the same analysis.

If we have 3 of them, we have 3 combinations.

B-B-B-G-G, G-B-B-B-G, G-G-B-B-B

If we have 2 of them, we have 4 combinations

B-B-G-G-G, G-B-B-G-G, G-G-B-B-G, G-G-G-B-B

then we have 1 + 3 + 3 + 4 = 11 combinations

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