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3 years ago

#1: Solve the inequality below. -3x + 5 < -19

Mathematics

1 answer:

frosja888 [35]3 years ago

4 0

Explanation: Just like any of your two-step equations,

in this inequality, start by isolating the x term which in this

case is -3x by subtracting 5 from both sides.

That leaves you with -3x < -24.

To get x by itself, divide both sides by -3 but watch out.

When you multiply or divide both sides of an inequality by a

negative number, you must switch the direction of the inequality sign.

So we have x < 8 and put your final answer in

set notation and it look like this → {x: x < 8}.

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Question:

Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0

Answer:

The number of real solutions for the equation $x^{2}+5 x+7=0$ is zero

Solution:

For a Quadratic Equation of form : $a x^{2}+b x+c=0$ ---- eqn 1

The solution is $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now , the given Quadratic Equation is $x^{2}+5 x+7=0$ ---- eqn 2

On comparing Equation (1) and Equation(2), we get

a = 1 , b = 5 and c = 7

In $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ , $b^2 - 4ac$ is called the discriminant of the quadratic equation

Its value determines the nature of roots

Now, here are the rules with discriminants:

1) D > 0; there are 2 real solutions in the equation

2) D = 0; there is 1 real solution in the equation

3) D < 0; there are no real solutions in the equation

Now let solve for given equation

$D= b^2 - 4ac\\\\D = 5^2 - 4(1)(7)\\\\D = 25 - 28 \\\\D = -3$

Since -3 is less than 0, this means that there are 0 real solutions in this equation.

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