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murzikaleks [220]
3 years ago
5

Write the following in expanded form then in word form . number 355,645​

Mathematics
1 answer:
valkas [14]3 years ago
3 0

Answer:

300000+50000+5000+600+40+5

word form:- three lakh fifty five thousand six hundred forty five.

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! <br><br> What is (f/g)(x) ?
Rudiy27

Answer:   \bold{D.\ \dfrac{x+4}{x}\ where\ x \neq 0, \dfrac{2}{3}}

<u>Step-by-step explanation:</u>

f(x) = 3x² + 10x - 8

g(x) = 3x² - 2x


\dfrac{f(x)}{g(x)}=\dfrac{3x^2+10x-8}{3x^2-2x}=\dfrac{(3x-2)(x+4)}{x(3x-2)}=\dfrac{x+4}{x}

Restriction on x: the denominator cannot be equal to zero. So,

    x(3x - 2) ≠ 0  

→  x ≠ 0     and     3x - 2 ≠ 0

                             3x       ≠ 2

                               x       \neq \dfrac{2}{3}


8 0
3 years ago
When e = 4, f = 2, and g = 8If e varies jointly with f and g, what is the constant of variation?
tatyana61 [14]

Answer:

e=\frac{1}{4} fg

Step-by-step explanation:

Joint variation problem  solve using the equation y = kxz.

e ∝ fg

e=kfg

now substitute the values

4=k*2*8\\4=16k\\k=\frac{4}{16} \\k=\frac{1}{4}

The relationship will be:

e=kfg\\e=\frac{1}{4} fg

8 0
3 years ago
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What is the solution to the equation? 2x - 4 = 6
rusak2 [61]

Answer:

x = 5

Step-by-step explanation:

2x -4 = 6

Add +4 on both sides

2x = 10

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x = 5

6 0
3 years ago
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Please help answer number 1
steposvetlana [31]
Maybe it’s consistent dependent
7 0
2 years ago
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Enter your answer and show all the steps that you use to solve this problem in the space provided.
rodikova [14]

Answer:

\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}

Step-by-step explanation:

f(x) = 9x³ + 2x² - 5x + 4; g(x)=5x³ -7x + 4

Step 1. Calculate the difference between the functions

(a) Write the two functions, one above the other, in decreasing order of exponents.

ƒ(x) = 9x³ + 2x² - 5x + 4

g(x) = 5x³           - 7x + 4

(b) Create a subtraction problem using the two functions

        ƒ(x) =    9x³ + 2x² - 5x + 4

      -g(x) =  <u>-(5x³           - 7x + 4) </u>

ƒ(x) -g(x)=

(c). Subtract terms with the same exponent of x

        ƒ(x)   =    9x³ + 2x² - 5x + 4

      -g(x)  =   <u>-(5x³          -  7x + 4) </u>

ƒ(x) -g(x) =      4x³ + 2x² + 2x

Step 2. Factor the expression

y = 4x³ + 2x² + 2x

Factor 2x from each term

y = 2x(2x² + x + 1)

\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}

5 0
3 years ago
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