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GrogVix [38]
3 years ago
7

If it takes 5 years for an animal population to double, how many years will it take until the population

Mathematics
1 answer:
muminat3 years ago
6 0

9514 1404 393

Answer:

  7.92 years

Step-by-step explanation:

We want to find t such that ...

  3 = 2^(t/5)

where 2^(t/5) is the annual multiplier when doubling time is 5 years.

Taking logs, we have ...

  log(3) = (t/5)log(2)

  t = 5·log(3)/log(2) ≈ 7.92 . . . years

It will take about 7.92 years for the population to triple.

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About 7% of the population has a particular genetic mutation. 400 people are randomly selected. Find the standard deviation for
Deffense [45]

Answer:

5.10 people

Step-by-step explanation:

Calculation to Find the standard deviation for the number of people with the genetic mutation

Using this formula

Standard deviation = √ ( n * p * q)

Where,

n = 400

p = .07

q = 100%-7% = 93% or .93

Let plug in the formula

Standard deviation =√400*07*.93

Standard deviation =√26.04

Standard deviation = 5.10 people

Therefore the standard deviation for the number of people with the genetic mutation is 5.10 people.

5 0
3 years ago
If the temperature in the Arctic is -13C, but it then rises by 20C, what is the new temperature?
miv72 [106K]

Answer:7

Step-by-step explanation:

all you have to do is subtract 20-13

4 0
2 years ago
Identify the polynomial. a ^2 + bcd ^3
Tpy6a [65]
B, binomial. 2 terms 

Hope that helps 
8 0
3 years ago
Read 2 more answers
In two or more complete sentences, compare the number of x-intercepts in the graph of f(t) = t^2 to the number of x-intercepts i
Anvisha [2.4K]
Well, minusing 8 from every t just moved theh function to the right 8 units
it had no effect on the number of t intercepts (horizontal is t axis instaead of x axis)

originally, it has 1 t intercept at t=0
now it still has 1 t intercept, but now it is at t=8
3 0
3 years ago
A scientist has a sample of bacteria that initially contains 10 million microbes. They observe the sample and finds that the num
sergiy2304 [10]

Answer:

M(t) = 6.7 * 10⁷ (67 million)

Minutes (t) =55

Step-by-step explanation:

1. Write an exponential equation that represents M, the total number of bacterial microbes in millions, as a function of t, the number of minutes the sample has been observed.

For answering this question, we will use the following formula:

M(t) = B₀ * g ^(t/m), where:

•M(t) represents the total number of bacterial microbes in millions.

• B₀ represents the initial population of bacteria in millions.

• g represents the growth factor.

• t represents the total number of minutes we will observe the bacteria growing.

• m represents the time in minutes it takes to the growth factor g to occur.

2. Then, determine how much time, to the nearest minute, will pass until there are 67 million bacterial microbes.

M(t) = B₀ * g ^(t/m)

Replacing with the values we know:

6.7 * 10⁷ = 10⁷ * 2 ^(t/20)

6.7 = 2 ^(t/20) (Dividing by 10⁷ at both sides)

ln 6.7 = ln 2 ^(t/20)

ln 6.7 = t/20 ln 2

ln 6.7/ ln 2 = t/20

t = ln 6.7/ln 2 * 20

t = 2.74 * 20

t = 54.88

t ≅ 55 (rounding to the nearest minute)

3 0
3 years ago
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