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Alla [95]
3 years ago
12

what is an equation of the line that passes through the point(-5,-5) and is parallel to the line 3x-5y=25​

Mathematics
1 answer:
sp2606 [1]3 years ago
3 0

Answer:

3x - 5y = 10

Step-by-step explanation:

Here's a fast but perfectly valid way to solve this problem:

Start with  3x-5y=25​ ; replace that constant, 25, with C:

3x - 5y = C

Now plug in y = -5 and x = -5, obtaining:

3(-5) - 5(-5) = C

Then -15 + 25 = 10, and so C = 10, and:

3x - 5y = 10 is the desired equation of the new line.

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Does anyone know the answer to this question.....0.5x + 1.75 = 10
marysya [2.9K]

Answer:

x = 16.5

Step-by-step explanation:

0.5x + 1.75 = 10

Subtract 1.75 from both sides:

0.5x = 8.25

Divide both sides by 0.5

x = 16.5

Check your work!

0.5(16.5) + 1.75 = 10

8.25 + 1.75 = 10

10 = 10

x = 16.5

3 0
3 years ago
Find x and y. <br><br> pls pls help
Anna [14]

Answer:

x = 65 , y = 64

Step-by-step explanation:

y - 16 and 2y + 4 are same- side interior angles and sum to 180° , that is

y - 16 + 2y + 4 = 180

3y - 12 = 180 ( add 12 to both sides )

3y = 192 ( divide both sides by 3 )

y = 64

then

2y + 4 = 2(64) + 4 = 128 + 4 = 132

the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

2y + 4 is an exterior angle of the triangle , then

x + 67 = 132 ( subtract 67 from both sides )

x = 65

7 0
1 year ago
Help help help ASAP math math
Lorico [155]
29 mg = 0.029 g hope this helps
4 0
2 years ago
Read 2 more answers
6464 is 444 times the difference between Sarah's age, aaa, and 444444. Assume Sarah is older than 44
xxMikexx [17]

Answer:

60 years

Step-by-step explanation:

Given that :

Sarah's age = a

Assume Sarah is older than 44 ; then a > 44

64 = 4 times difference between a and 44

Expressing the problem mathematically ;

64 = 4 * (a - 44)

64 = 4a - 176

64 + 176 = 4a

240 = 4a

a = 240 / 4

a = 60

Hence, Sarah is aged 60

5 0
3 years ago
Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t
Svet_ta [14]

Answer:

[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}

[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}

[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]

Finally, the third vector of basis E is e3(t)=t^{2}

T[e3(t)]=T(t^{2})

in the equation : a2 = 1

T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}

Then

[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]

And that is the third column of [T]EE

Let's write our matrix

[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

X=\left[\begin{array}{c}1&0&0\\\end{array}\right]

AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]

Applying the coordinates 2,6 and -2 to the basis E we obtain

2+6t-2t^{2}

That was the original result of T[e1(t)]

8 0
3 years ago
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