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Tpy6a [65]
2 years ago
14

Find the area of this parallelogram. A) 35 cm B) 75 cm C) 105 cm D) 150 cm

Mathematics
1 answer:
docker41 [41]2 years ago
7 0

Answer:

B) 75 cm

Step-by-step explanation:

A = bh

(b =base & h = height)

therefore

area = 5 × 15

= 75 cm

I think this will helpful to you

give me a brainliest

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Susie ran a total of 181.8 minutes in 9 days. If she ran for the same amount of time each day, how many minutes did she run per
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Answer:

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Step-by-step explanation:

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  \dfrac{18n^6}{2n^2}=\dfrac{18}{2}n^{6-2}=9n^4

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For what values of $x$ is $$\frac{x^2 + x + 3}{2x^2 + x - 6} \ge 0?$$ note: be thorough and explain why all points in your answe
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To solve the inequality \frac{x^2+x+3}{2x^2+x-6}\ge \:0

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The numerator x^2+x+3 is not factorizable.

so factor the denominator 2x^2+x-6:

2x^2+x-6=\left(2x^2-3x\right)+\left(4x-6\right)=x\left(2x-3\right)+2\left(2x-3\right)\\ \mathrm{Factor\:out\:}x\mathrm{\:from\:}2x^2-3x\mathrm{:\quad }x\left(2x-3\right)\\ \mathrm{Factor\:out\:}2\mathrm{\:from\:}4x-6\mathrm{:\quad }2\left(2x-3\right)\\

Now take \mathrm{Factor\:out\:common\:term\:}\left(2x-3\right)

Then we get factor of the denominator as \left(2x-3\right)\left(x+2\right)

Thus \frac{x^2+x+3}{2x^2+x-6}=\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}

Now \mathrm{Compute\:the\:signs\:of\:the\:factors\:of\:}\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}\\

Signs of x^2+x+3>0

\mathrm{Choosing\:ranges\:that\:satisfy\:the\:required\:condition:}\:\ge \:\:0

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