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Anastaziya [24]
2 years ago
5

A scuba diver is swimming 15 feet below the water’s surface.

Mathematics
1 answer:
enyata [817]2 years ago
5 0

Answer:

3.2

Step-by-step explanation:

every ten is a whole number

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The circumference of a circular field is 276 yards. What is the diameter of the field? Round your answer to the nearest hundredt
stiv31 [10]

Answer:

d ≈ 87.85 yards

Step-by-step explanation:

The circumference ( C) of a circle is calculated as

C = πd ( d is the diameter ), then

276 = πd ( divide both sides by π )

\frac{276}{\pi } = d , so

d ≈ 87.85 yards ( to the nearest hundredth )

6 0
3 years ago
Can I get help with this please
Tanya [424]

Answer:

10d or less

Step-by-step explanation:

Joanne would want $50 left, and she has $250. 20 - 50 is 200. 20 goes into 100 5 times.

20 goes into 200 10 times. You just add five. (20, 40, 60, 80, 100)

If she wants at least $50 left, she would have to limit how many Dvd's she buys to 10 or less.

8 0
2 years ago
HELP PLEASE!!! EASY I just haven't done algebra in a while so I forgot lol.
ElenaW [278]

Answer:

wait.. almost done...

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Which ordered pair is a solution to the system of linear equations 1/2x-3/4y=11/60 and 2/5x+1/6y=3/10
Leona [35]

Answer:

(\frac{2}{3} , \frac{1}{5})

Step-by-step explanation:

The fastest way to do this is to convert both equations into slope-intercept form and graph it to find the solution point. If you wanted to do this algebraically, you might want to start out by getting rid of the fractions and using either substitution or elimination to find x and y.

4 0
3 years ago
Need help vrtfv fvvfgsf
maksim [4K]

Answer:

b = 8

Step-by-step explanation:

Use the Pythagorean theorem

c^2 = a^2 + b^2  

c = 10

a = 6

b = ?

Substitute into the formula

10^2 = 6^2 + b^2      

100 = 36 + b^2            Subtract 36 from both sides

100 - 36 = b^2             Combine

64 = b^2                      Take the square root of both sides.

√64 = √b^2

b = 8

7 0
2 years ago
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