What is 3 fifths times one and 1third

In the book Essentials of Marketing Research, William R. Dillon, Thomas J. Madden, and Neil H. Firtle discuss a research proposa

MakcuM [25]

Answer:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

$z=\frac{0.179-0.15}{\sqrt{0.17(1-0.17)(\frac{1}{140}+\frac{1}{60})}}=0.500$

$p_v =2*P(Z>0.500)=0.617$

So the p value is a very low value and using any significance level for example $\alpha=0.05, 0,1,0.15$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the two proportions NOT differs significantly.

Step-by-step explanation:

Data given and notation

$X_{1}=25$ represent the number of homeowners who would buy the security system

$X_{2}=9$ represent the number of renters who would buy the security system

$n_{1}=140$ sample 1

$n_{2}=60$ sample 2

$p_{1}=\frac{25}{140}=0.179$ represent the proportion of homeowners who would buy the security system

$p_{2}=\frac{9}{60}= 0.15$ represent the proportion of renters who would buy the security system

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the two proportions differs , the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{25+9}{140+60}=0.17$

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.179-0.15}{\sqrt{0.17(1-0.17)(\frac{1}{140}+\frac{1}{60})}}=0.500$

Statistical decision

For this case we don't have a significance level provided $\alpha$ , but we can calculate the p value for this test.

Since is a two sided test the p value would be:

$p_v =2*P(Z>0.500)=0.617$

So the p value is a very low value and using any significance level for example $\alpha=0.05, 0,1,0.15$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the two proportions NOT differs significantly.

6 0

3 years ago

PLZ HELP ASAP WILL MARK BRAINLIEST !!!!!Either Table C or Table D shows a proportional relationship.

NNADVOKAT [17]

Answer:

Table C

Step-by-step explanation:

Now where is my Brainliest XD

7 0

3 years ago

Read 2 more answers

Kelly needs $125 to buy a dress for the dance. Her dad gave her five dollars for doing your chores and received $15 an hour to t

Debora [2.8K]

8 hours. 125 - 5 = 120. 120 / 15 = 8. Kelly will need to tutor for 8 hours minimum to buy the dress.

7 0

3 years ago

Water fills a tank at a rate of 150 litres during the first hour, 350 litres during the second, 550 litres during the third and

Alborosie

Putting this as an arithmetic sequence gives:

$u_n = 150+200(n-1)$

The sum of the series = 16 x 7 x 7 = 784 m^3 = 784 000 L

The sum of an arithmetic series can be written as:

$S_n=n/2 [2a+(n-1)d] = 784 000
\\n/2[2(150)+(n-1)200] = 784 000
\\n[300+200(n-1)=1 568 000
\\300n+200n^2-200n = 1 568 000
\\200n^2+100n- 1 568 000 = 0
\\2n^2 +n- 15680 = 0

\\n= 88.2...,-88.7$

n has to be positive, so we get

n = <u>88.2 hours (3 s.f.)</u>

3 0

3 years ago

Read 2 more answers

X/3 +2y/3= -1 and x-y/3=9 solve. by elimination method

Galina-37 [17]

Answer:

X=51/7, Y= -36/7

Step-by-step explanation:

X/3 + 2y/3 = -1 equ 1

X - y/3 = 9 equ 2

eliminate X/3.

X/3 + 2y/3 = -1..... x 1 ( co-efficient of X in equ2 )

X - y/3 = 9 ...... x 1/3 ( co-efficient of X in equ1 )

X/3 + 2y/3 = - 1 equ 3

-

X/3 - y/9 = 3 equ 4

0 + 7y/9 = -4

y = -36/7

( input the value of y into equ 4 )

X/3 -y/9 = 3

X/3 - (-36/7)/9 = 3

X/3 + 36/63 = 3

X/3 = 3 - 36/63

X/3 = 153/63

63X = 459

X = 459/63

X = 51/7.

8 0

3 years ago