All categories

2 years ago

What is 3 fifths times one and 1third

1 answer:

4 0

3/5 x 1 1/3

Turn to an improper fraction (it's easier for me xP)
3 4
---- x ----
5 3

Solve
3 4 12
---- x ---- = ------
<span> 5 3 15
</span>
Simplify
12 ÷ 3 = 4
----- ----
15 ÷ 3 = 5

4/5 is your answer

You might be interested in

Write this trinomial in factored form 2a^2 +7a+3

EleoNora [17]

Answer:

(2a + 1)(a + 3) = 2a² + 7a + 3

8 0

2 years ago

Need help with full work quick

vekshin1

Answer:

Step-by-step explanation:

36x^3 - 81x

9x(4x^2 - 9)

9x(2x - 3)(2x + 3)

She is right

4 0

2 years ago

The numbers 5 and -5 are opposites.explain why 5 and -5 have the same absolute value

Citrus2011 [14]

Answer:

I think because the absolute value is always a positive number.

Step-by-step explanation:

3 0

1 year ago

Help please!!! I just seriously need help I'm bad at math>

azamat

There is only 1 real number solution

8 0

2 years ago

If y-3x=9, 7x+y=25, what is the value of x and y?

lianna [129]

$\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?$

$\bold{\rm{Solution}} \text{: We'll solve this by substitution method}$

$\dashrightarrow y - 3x = 9 \\ \\ \dashrightarrow \boxed{y = 9 + 3x } \qquad .. \sf eq(1)$

$\text{we got the value of y now getting the value of x}$

$\looparrowright 7x + y = 25 \\ \\ \looparrowright 7x = 25 - y \\ \\ \looparrowright \boxed{x = \frac{25 - y}{7}} \qquad .. \sf eq(2)$

$\text{Now, putting y = 9 + 3x in eq(2)}$

$\hookrightarrow x = \frac{25 - y}{7} \\ \\ \hookrightarrow x = \frac{25 - 9 + 3x}{7} \\ \\ \hookrightarrow 7x = 25 - 9 + 3x \\ \\ \hookrightarrow 7x - 3x = 16 \\ \\ \hookrightarrow 4x = 16 \\ \\ \hookrightarrow x = \frac{16}{4} \\ \\ \star \quad \boxed{ \green{ \frak{ x = 4}}}$

$\text{Now we know the value of x, for getting y we need to put x in eq(1)}$

$: \implies y = 9 + 3x \\ \\ : \implies y = 9 + 3(4) \\ \\ : \implies y = 9 + 12 \\ \\ \star \quad \boxed{\frak{ \green{y = 21}}}$

$\text{Hence, values of x and y are} \: \frak{ \green{4}} \: \text{and} \: \frak{ \green{21}} \: \text{respectively}.$

4 0

1 year ago