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2 years ago

12

Whats the answer to 7x10¹=7x10=

1 answer:

tekilochka [14]2 years ago

7 0

The answer to 7×10 is 70. Multiplication is fast adding. For example, 10+10+10+10+10+10+10=70

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The Elster family drove 9.25 hours on the first day of their road trip. How many minutes is this equivalent to?

butalik [34]

Answer:

555 minutes

Step-by-step explanation:

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3 years ago

Find the midpoint of the segment with the following endpoints.<br> (1,-10) and (8,-4)

vlada-n [284]

Answer:

(4.5,-7)

Step-by-step explanation:

you add the x coordinates then divide them by 2

And then add the y coordinates then divide them by 2 also

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3 years ago

The equation 24x2+25x−47ax−2=−8x−3−53ax−2 is true for all values of x≠2a, where a is a constant.

laila [671]

Im 75% sure the answer is -3.

5 0

2 years ago

Read 2 more answers

PLEASE HELP ASAP -- WITH THE WORKK<br><br>50 points

MAXImum [283]

Part-A:-

<h3>(f×g)=</h3>

$\\ \sf\longmapsto x^2+3x-70(4x-12)$

$\\ \sf\longmapsto 4x^2+12x-280-12x^2+36x+840$

$\\ \sf\longmapsto -8x^2+48x+560$

Now

$\\ \sf\longmapsto (f.g)(3)$

$\\ \sf\longmapsto -8(3)^2+48(3)+560$

$\\ \sf\longmapsto -72+144+560$

$\\ \sf\longmapsto 72+560$

$\\ \sf\longmapsto 632$

Part-B:-

$\\ \sf\longmapsto f(3)$

$\\ \sf\longmapsto (3)^2+3(3)-70$

$\\ \sf\longmapsto 9+9-70$

$\\ \sf\longmapsto 18-70$

$\\ \sf\longmapsto -52$

Now

$\\ \sf\longmapsto g(f(3))$

$\\ \sf\longmapsto g(-52)$

$\\ \sf\longmapsto 4(-52-3)$

$\\ \sf\longmapsto 4(-55)$

$\\ \sf\longmapsto -220$

Part:-C

$\\ \sf\longmapsto g(-2)$

$\\ \sf\longmapsto 4(-2-3)$

$\\ \sf\longmapsto 4(-5)$

$\\ \sf\longmapsto -20$

Now

$\\ \sf\longmapsto f(g(-2))$

$\\ \sf\longmapsto f(-20)$

$\\ \sf\longmapsto (-20)^2+3(-20)-70$

$\\ \sf\longmapsto 400-60-70$

$\\ \sf\longmapsto 400-130$

$\\ \sf\longmapsto 270$

Part-D:-

g×f=f×g

$\\ \sf\longmapsto (g.f)(-2)$

$\\ \sf\longmapsto -8(-2)^2+48(-2)+560$

$\\ \sf\longmapsto 32-96+560$

$\\ \sf\longmapsto -64+560$

$\\ \sf\longmapsto 496$

6 0

2 years ago

The drama club collected $160 from ticket sales for the spring play. They need to collect at least $400 to pay for new lighting

valentina_108 [34]

We assume all money is spent on new lighting. Since they currently have $160 and need $400 we can subtract what they currently have from what they need.

$400-$160 = $240

Since we know the price of the ticket and now know they need $240 we can divide our $240 with the price of each ticket ($3)

$240/$3 = 80

So the drama club has to sell 80 more tickets in order to afford new lighting

6 0

2 years ago