Answer:
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Step-by-step explanation:
Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.
Initial velocity u with which the ball is projected upwards = + 120 ft/s
Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Using the formula:
v² - u² = 2 a h,
where
u = initial velocity of the ball = +120 ft/s
v = final velocity of the ball at the highest point = 0 ft/s
a = uniform acceleration acting on the ball = -32 ft/s²
h = height attained
Substituting the values we get;
0² - 120² = 2 × (- 32) h
=> h = 120²/2 × 32 = 225 feet
The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.
Answer:
The height of the cylinder is 4x units.
Step-by-step explanation:
volume of a cylinder = nr^2h
n = 22/7
r = radius = x/2
Let illustrate with an example. If the diameter of a cylinder is 6 and the volume is 6^3 = 216. The radius = 6/2 = 3
n3^2 x h = 216
h = 216/9 = 24
so the height is 4 times the diameter
Area of the base = nr^2
1/2^2 x x = 1/4 pi x^2
The table was <em><u>22.5 inches wide</u></em>.
hope this helps!
Top answer is -4 because when you divide by a negative your answer will come out negative and bottom answer is 6 because when you multiply two negatives it turns into a positive
If y is directly proportional to x then y:x.
When y = 30, x = 6 then 30/6 = 5:1. Therefor for every 1x there is 5y vice versa. When x = 12, then y = 5 * 12 = 60.
Therefore y = 60 hence 60:12
