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BabaBlast [244]
3 years ago
13

A board is cut so that its length is changed from 8 feet to 6.5 feet. What is the percent of change in length? Round your answer

to the nearest tenth, if necessary. a. –18.8% c. 18.8% b. –23.1% d. 81.2%
Mathematics
1 answer:
Schach [20]3 years ago
3 0

it went from 8 to 6.5, namely 8 - 6.5 = 1.5.


if we take the 8 to be the 100%, what is 1.5 off of it in percentage?


\bf \begin{array}{ccll}amount&\%\\\cline{1-2}8&100\\1.5&x\end{array}\implies \cfrac{8}{1.5}=\cfrac{100}{x}\implies x=\cfrac{1.5\cdot 100}{8}\implies x=18.75


well, we can round that up to 18.8%, however since it's a subtraction from the board, we can say is -18.8%, a negative percent, because is a percent that was taken out of it.

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Answer:

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Step-by-step explanation:

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Can someone pls answer 150 divided by 30
Svetlanka [38]

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5

Step-by-step explanation:

150/30 = 15/3 = 5

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62.8 feet

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Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive
VikaD [51]
Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

\bf csc(\theta)=-6\implies csc(\theta)=\cfrac{\stackrel{hypotenuse}{6}}{\stackrel{opposite}{-1}}\impliedby \textit{let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\pm\sqrt{6^2-(-1)^2}=a\implies \pm\sqrt{35}=a\implies \stackrel{IV~quadrant}{+\sqrt{35}=a}

recall that 

\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad\qquad 
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\\\\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\\\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}

therefore, let's just plug that on the remaining ones,

\bf sin(\theta)=\cfrac{-1}{6}
\qquad\qquad 
cos(\theta)=\cfrac{\sqrt{35}}{6}
\\\\\\
% tangent
tan(\theta)=\cfrac{-1}{\sqrt{35}}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{\sqrt{35}}{1}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}

now, let's rationalize the denominator on tangent and secant,

\bf tan(\theta)=\cfrac{-1}{\sqrt{35}}\implies \cfrac{-1}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{-\sqrt{35}}{(\sqrt{35})^2}\implies -\cfrac{\sqrt{35}}{35}
\\\\\\
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g100num [7]

Answer:

54

Step-by-step explanation:

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216 out of 400 turned into percentage is 54

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