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3 years ago

7

How do I solve this?

1 answer:

crimeas [40]3 years ago

7 0

Answer:

The final answer is (2,-1)

(also idek what I did in the photo but I'm positive the answer is (2,-1)

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I don't know how to do this. Any help?

Brut [27]

Answer:

cos 37=x/b (second one)

sin 37= a/b (third one)

tan 37=a/x (sixth one)

Step-by-step explanation:

Cos is defined by the adjacent side over the hypotenuse. Cos 37 would be x/b. Clearly, that is option 2. Sin is defined by opposite over hypotenuse. Sin 37 would be a/b. That is the 3rd option. Tan is defined by opposite over adjacent. Tan 37 would be a/x or the 6th option.

7 0

3 years ago

PLEASE HELP PLA

aleksley [76]

Answer:

$y = -x+8$

Step-by-step explanation:

The side that is parallel to BC is EF

Find the slope of EF:

$m = \frac{2-4}{6-4} =\frac{-2}{-2} =-1$

Easiest way is just put the formula in point-slope form and simplify.

Let's use point F, which is (6,2)

$y -2=-(x-6)$

Simplify:

$y-2=-x+6$

Add 2 on both sides:

$y = -x+8$

Hope this helped

5 0

2 years ago

Read 2 more answers

What is the probability that the sun will not rise Tomorrow plz explain?

Luba_88 [7]

Answer:

the sun may rise or will not rise , so there are 2 chances

Step-by-step explanation:

so the probability is 1/2=0.5

6 0

3 years ago

Whats 3/8 + 3 7/12=?

kow [346]

Answer:

3.95833333333

Step-by-step explanation:

3 0

3 years ago

1. Given points A(3, -5) and B(19, -1), find the coordinates of point C that sit 3/8 of the way along line AB, closer to A than

zaharov [31]

1. C(x, y) = (7.3, –3.9)

2. C(x, y) = (17, –1.5)

Solution:

Question 1:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction $\frac{3}{8}$ .

Point divides segment in the ratio formula:

$$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)$

Here, $x_1=3, y_1=-5, x_2=19, y_2=-1$ and m = 3, n = 8

$$C(x, y)=\left(\frac{3\times19+8\times3}{3+8} , \frac{3\times(-1)+8\times(-5)}{3+8}\right)$

$$=\left(\frac{57+24}{11} , \frac{-3-40}{11}\right)$

$$=\left(\frac{81}{11} , \frac{-43}{11}\right)$

C(x, y) = (7.3, –3.9)

Question 2:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction $\frac{3}{8}$ .

Point divides segment in the ratio formula:

$$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)$

Here, $x_1=3, y_1=-5, x_2=19, y_2=-1$ and m = 7, n = 1

$$C(x, y)=\left(\frac{7\times19+1\times3}{7+1} , \frac{7\times(-1)+1\times(-5)}{7+1}\right)$

$$=\left(\frac{133+3}{8} , \frac{-7-5}{8}\right)$

$$=\left(\frac{136}{8} , \frac{-12}{8}\right)$

C(x, y) = (17, –1.5)

8 0

3 years ago