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ss7ja [257]
4 years ago
14

Steve can complete the hundred meter dash in 10 seconds while Paul can run it in 12 seconds how does Steve's time compared to Pa

ul's
Mathematics
2 answers:
Mkey [24]4 years ago
6 0
Steve ran 2 seconds faster then Paul did
erma4kov [3.2K]4 years ago
5 0
Steve is fast beacuse he faster then paul  :)
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How to do it? Its URGENT​!!!I need it right now!!!?!? I will give 10 points! Pls!!!
ololo11 [35]
<h3>A manufacturer sells an item to an agency at a profit of 25%. The agency sells the item to a shopkeeper at 10% profit and shopkeeper sells the item at a profit of 20%. If the selling price of the item is $594, find the manufacturing price.</h3>

Answer: $360

Step-by-step explanation:

Let Mp the manufacturing price.

First step:

Manufacturer sells at a profit of 25% = Mp + Mp·0.25 = Mp·1.25

Second step:

Agency sells at a profit of 10% = 1.25Mp + 1.25Mp·0.10 = Mp·1.375

Third step:

Shopkeeper sells at a profit of 20% = 1.375Mp + 1.375Mp·0.20 = Mp·1.65

Then the final price = 1.65·Mp

1.65Mp = $594

Mp = $594/1.65 = $360 ►Manufacturer price

Answer: $360

Verification

Manufacturer sells at a profit of 25% = 25/100 = 0.25:

$360 + $360·0.25 = $360(1 + 0.25) = $360 + $90 = $450

Agency sells at a profit of 10% = 10/100 = 0.10:

$450 + $450·0.10 = $450(1 + 0.10) = $450 + $45 = $495

Shopkeeper sells at a profit of 20% = 20/100 = 0.20

$495 + $495·0.20 = $495(1 + 0.20) = $495 + $99 = $594 Checked!

\textit{\textbf{Spymore}}

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3 years ago
There are 104 students in the fourth grade
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Answer: 89 4th grader

Step-by-step explanation:

8 0
3 years ago
If f(x) = x/2 - 3 and g(x) = 3x^2 + x - 6, find (f+g)(x)
drek231 [11]

(f+g)(x) = f(x) +g(x)

(f+g)(x) = \left(\dfrac{x}{2}-3\right)+\left(3x^2+x-6\right)

(f+g)(x) =3x^2 +\dfrac{3x}{2}-9

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3 years ago
Two lines are perpendicular. The equation of the first line is y = 4x + 1. Which of the following cannot be the equation of the
zalisa [80]
The answer is letter B
7 0
3 years ago
Read 2 more answers
Use the position equation given below, where s represents the height of the object (in feet), v0 represents the initial velocity
iris [78.8K]

Answer:

(a) 7.5 seconds

(b) The horizontal distance the package  travel during its descent is 1737.8 ft

Step-by-step explanation:

(a) The given function for the height of the object is s = -16·t² + v₀·t + s₀

The initial height of the object s₀ = 900 feet

The initial vertical velocity of the object v₀_y = 0 m/s

The time it takes the package to strike the ground is found as follows;

0 = -16·t² + 0×t + 900

900 = 16·t²

t² = 900/16 = 62.25

t = √62.25 = 7.5 seconds

(b) Given that the horizontal velocity of the package is given as 158 miles/hour, we have

158 miles/hour = 231.7126 ft/s

The horizontal distance the package  covers in the 7.5 second of vertical flight = 231.7126 ft/s × 7.5 s = 1737.8445 feet = 1737.8 ft to one decimal place

The horizontal distance the package  travel during its descent = 1737.8 ft.

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3 years ago
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