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3 years ago

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A rectangular pool is surrounded by a walk 3 meters wide. The pool is 5 meters longer than its width. If the total area of the p

ool and walk is 246 square meters more than the area of the pool, find the dimensions of the pool.

1 answer:

kaheart [24]3 years ago

3 0

Answer:

hhthththhth

Step-by-step explanation:

htrthrthrthr

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PLEASE HELP ME ILL GIVE BRAINLIEST

victus00 [196]

Answer:

-36.5

Step-by-step explanation:

substitute 8.5 for v

8-(6(8.5)+2-(8.5))

8-(51+2-8.5)

8-44.5

edited cause I forgot the 8 at first :P

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4 years ago

What is the value of x in the equation 8 + x = 3?<br><br> A. −5<br> B. 5<br> C. 11<br> D. 24

zlopas [31]

Answer:

I think it's A

I hope this helps

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3 years ago

Read 2 more answers

What is the solution of the equation (x – 5)^2 + 3(x – 5) + 9 = 0? Use u substitution and the quadratic formula to solve.

xz_007 [3.2K]

Answer:

$x = \dfrac{7 \pm 3i\sqrt{3}}{2}$

Step-by-step explanation:

(x – 5)^2 + 3(x – 5) + 9 = 0

This is a quadratic equation in x - 5.

Let u = x - 5, then the quadratic equation becomes:

u^2 + 3u + 9 = 0

We can use the quadratic formula to solve for u.

$u = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

$u = \dfrac{-3 \pm \sqrt{3^2 - 4(1)(9)}}{2(1)}$

$u = \dfrac{-3 \pm \sqrt{9 - 36}}{2}$

$u = \dfrac{-3 \pm \sqrt{-27}}{2}$

$u = \dfrac{-3 \pm 3i\sqrt{3}}{2}$

Since u = x - 5, now we substitute x - 5 for u and solve for x.

$x - 5 = \dfrac{-3 \pm 3i\sqrt{3}}{2}$

$x = \dfrac{-3 \pm 3i\sqrt{3}}{2} + 5$

$x = \dfrac{-3 \pm 3i\sqrt{3}}{2} + \dfrac{10}{2}$

$x = \dfrac{7 \pm 3i\sqrt{3}}{2}$

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3 years ago

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disa [49]

1. X=3
Use Photomath for the rest

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3 years ago

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Gnesinka [82]

Step-by-step explanation:

1) The very first thing to do is read and write down the given data carefully.

From here we can decipher if the intersect asked her is SIMPLE INTEREST or COMPOUND INTEREST.

2) Next step is to put the given values in the appropriate formula correctly and decipher what value is needed to be found.

3) The final step is to do the neat calculations so that there is no error while doing it.

By this we can compute the desired value correctly.

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3 years ago