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Gre4nikov [31]
3 years ago
12

How do I find the perimeter of similar triangles? (Geometry)

Mathematics
1 answer:
Igoryamba3 years ago
6 0
I hope this helps you




3y-2=y+4



2y=6


y=3



Perimeter=4+6+7



Perimeter=17
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Answer:

q(x)= \frac{1}{3} x -\frac{13}{3}

Step-by-step explanation:

So you have (16, 1)

When two linear functions are parallel, they have the same slope.

So function q also has a slope of 1/3x. You have a set of points so you can plug them in a slope intercept equation to find b.

y= mx+b

m= slope

y= y-intercept

1= 1/3(16) +b

1 - (16/3) = b

b= -13/3

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Consider the equation: x^2+10x+22=13<br> Need help asap!!!! <br> this is due in a hour!
klio [65]

Answer:

(x + 5)^2 = (5 - 3)^2

Step-by-step explanation:

Given the equation;

x^2 + 10x + 22 = 13

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Adding half of 10 to both sides and completing the square as usual, we have;

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olchik [2.2K]
A = LW
A = 320
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320 = W(5W)
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so the length (L) = 40 cm and the width (W) = 8 cm

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4 0
3 years ago
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