Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
Answer:
5.86
Step-by-step explanation:
Answer:
11 5/9
Step-by-step explanation:
Answer:
B. (x+2) is a factor
Step-by-step explanation:
3x^2 -x-14
3x^2+6x-7x-14
3x(x+2)-7(x+2)
(3x-7)(x+2)
so, x+2 is a factor of 3x^2-x-14
