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Slav-nsk [51]
3 years ago
5

This also 7th fgrade homework!!

Mathematics
1 answer:
harkovskaia [24]3 years ago
6 0

Answer:

Down the left-hand column, the pattern is counting by 5's. Therefore, 5, 10, 15, 20, 25. Down the right-hand column, the pattern is counting by 4's. Therefore, 4, 8, 12, 16, 20. Thus, the ratios are:

5:4

10:8

15:12

20:16

25:20

In other words, the first line (5:4) is the base ratio. The second line multiplies the original values by 2, the third line by 3, the fourth line by 4, and the fifth line by 5.

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Three friends got jobs at stores in the mall. Nina earns $117.60 for hours 14 of work. Ty earns for $148.50 hours 18 of work. Ki
marysya [2.9K]

Answer:

Kim has the highest pay rate in dollars per hour

Step-by-step explanation:

we know that

To find out the unit pay rate divide the total earning by the total time

so

Nina earns $117.60 for hours 14 of work

\frac{117.60}{14}=\$8.4\ per\ hour

Ty earns for $148.50 hours 18 of work

\frac{148.50}{18}=\$8.25\ per\ hour

Kim earns for $137.60 hours 16 of work

\frac{137.60}{16}=\$8.60\ per\ hour

8.6 > 8.4 > 8.25

therefore

Kim has the highest pay rate in dollars per hour

6 0
3 years ago
Negative square root of nine is it a rational or irrational number
Sergio [31]

It's a rational number. 9 is a perfect square. What you have asked is written as -sqrt(9), which can be written as -sqrt(3*3) which is - 3. That's perfectly OK. What would not be OK is something like -sqrt(10) which is irrational because it cannot be represented as a fraction or a whole number or a repeating decimal or a decimal that terminates.

7 0
3 years ago
Read 2 more answers
Solve using algebraic equation: <br> 5sin2x=3cosx<br><br> (No exponents)
DaniilM [7]
5\sin2x=3\cos x\iff10\sin x\cos x=3\cos x

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

10\sin x\cos x=3\cos x\iff10\sin x\cos x-3\cos x=\cos x(10\sin x-3)=0

Now the zero product property tells us that there are two cases where this is true,

\begin{cases}\cos x=0\\10\sin x-3=0\end{cases}

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of \dfrac\pi2, so x=\dfrac{(2n+1)\pi}2 where n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}

which occurs twice in the interval [0,2\pi) for x=\arcsin\dfrac3{10} and x=\pi-\arcsin\dfrac3{10}. More generally, if you think of x as a point on the unit circle, this occurs whenever x also completes a full revolution about the origin. This means for any integer n, the general solution in this case would be x=\arcsin\dfrac3{10}+2n\pi and x=\pi-\arcsin\dfrac3{10}+2n\pi.
6 0
3 years ago
Find the lentgh of the missing side
adell [148]

Answer:

8 is missinn

8 ixxdxx

8 0
3 years ago
Maddy made $22.50 for babysitting for 5 hours for her aunt. Maddy was paid $21.00 for 3.5 hours of babysitting for her neighbor.
Greeley [361]

Answer:Her Aunt paid her 4.50 and hour and her neighbor 6 an hour. The difference is 1.5

Step-by-step explanation:

8 0
3 years ago
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