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Juliette [100K]
4 years ago
15

The cost of a car is $15,570. You plan to make a down payment of $1,500, and a monthly payment of $338.08 for 60 months. What is

the amount financed? Round your answer to the nearest dollar.
A - $20,285
B - $14,070
C - $21,784
D - $6,214

The cost of a car is $15,570. You plan to make a down payment of $1,500, and a monthly payment of $338.08 for 60 months. What is the total repaid? Round your answer to the nearest dollar.
A - $20,285
B - $14,070
C - $21,784
D - $6,214

The cost of a car is $15,570. You plan to make a down payment of $1,500, and a monthly payment of $338.08 for 60 months. What is the finance charge? Round your answer to the nearest dollar.
A - $20,285
B - $14,070
C - $21,784
D - $6,214

The cost of a car is $15,570. You plan to make a down payment of $1,500, and a monthly payment of $338.08 for 60 months. What is the total cost that will be paid? Round your answer to the nearest dollar.
A - $20,285
B - $14,070
C - $21,784
D - $6,214
Mathematics
2 answers:
Helga [31]4 years ago
4 0
Hi there
1) b
15,570−1,500
=14,070
2) a
338.08×60
=20,284.8
3)d
20,284.8−14,070
=6,214.8
4) c
338.08×60+1,500
=21,784.8

Hope it helps
Akimi4 [234]4 years ago
3 0

Answer:

Amount financed is $14070 .

Option (B) is correct .

Step-by-step explanation:

As given

The cost of a car is $15,570.

You plan to make a down payment of $1,500 and a monthly payment of $338.08 for 60 months.

Amount financed = Cost of the car - Down payment price

Putting values in the above

Amount financed = $15570 - $1500

                             = $ 14070

Therefore the amount financed is $14070 .

Option (B) is correct .


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1. Ensure the equations for both lines being compared are in the slope-intercept form, y = mx + b. Where m is the slope.

2. If both lines have the same slope value, m, then both lines are parallel.

3. If the slope of one line is the negative reciprocal of the other, then both lines are perpendicular. That is, x = -1/x.

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Both have the same slope value of 3. Therefore, they are parallel.

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