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s2008m [1.1K]
3 years ago
13

Does anyone know this and if it is extraneous or not?

Mathematics
1 answer:
Anna11 [10]3 years ago
5 0
Addd 4 to both sides
\sqrt{x+9}=5
sqare both sides
x+9=25
minus 9 both sides
x=16

plug it in for x and see
\sqrt{16+9}-4=1
\sqrt{25}-4=1
5-4=1
1=1
true

not extraneous
an extraneous root would be x=-34
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