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galben [10]
3 years ago
9

Solve: 3x-3y=3 y=-5x-17

Mathematics
1 answer:
ivolga24 [154]3 years ago
5 0
<span>Substitute y = -5x - 17 into the first equation:
-3x - 3y = 3
-3x - 3*(-5x - 17) = 3

-3x + 15x + 51 = 3
-3x + 15x = 3 - 51
12x = -48
x =-48/12 = -4 

y = -5x - 17 = -5*(-4) - 17 = 20 - 17 = 3 

so the solution is x = -4, y = 3</span>
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If sin x=2/9,x, in quadrant i, then find(without findingx): sin(2x), cos(2x), tan(2x)
Sergio039 [100]
We have that
<span>sin x=2/9

we know that
sin</span>² x+cos² x=1---------> cos² x=1-sin² x-----> cos² x=1-(2/9)²
cos² x=1-(4/81)------> (81-4)/81-----> 77/81
cos x=√(77/81)

Sin 2x = 2 sin x cos x-------> 2*(2/9)*(√(77/81))----> (4/81)*√77---> 0.43

Sin 2x=0.43
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tan 2x=sin 2x/cos 2x--------> tan 2x=0.43/0.9---------> tan 2x=0.48

the answers are
sin 2x=0.43
cos 2x=0.9
tan 2x=0.48


8 0
3 years ago
Write an equation in standard form for each line.
LenaWriter [7]

The standard form: Ax + By = C.

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}


7. We have the points (4, -7) and (2, -3). Substitute:

m=\dfrac{-3-(-7)}{2-4}=\dfrac{4}{-2}=-2\\\\y-(-7)=-2(x-4)\qquad|\text{use distributive property}\\\\y+7=(-2)(x)+(-2)(-4)\\\\y+7=-2x+8\qquad|-7\\\\y=-2x+1\qquad|+2x\\\\\boxed{2x+y=1}

8. We have the points (1, 5) and (-10, -6). Substitute:

m=\dfrac{-6-5}{-10-1}=\dfrac{-11}{-11}=1\\\\y-5=1(x-1)\\\\y-5=x-1\qquad|+5\\\\y=x+4\qquad|-x\\\\-x+y=4\qquad|\text{change the signs}\\\\\boxed{x-y=-4}


7 0
3 years ago
Instructions: Find the missing angle in the image below. Do not include spaces in your answers.​
vitfil [10]

Answer:

im not the best in math but I think its 95 since a line segment is 180 degrees and you add tge two number and subtract what you have

hope this hells

4 0
3 years ago
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