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zaharov [31]
3 years ago
13

Please Help!!! Fill in the blank: 8 + _ = 6

Mathematics
2 answers:
iragen [17]3 years ago
6 0

Answer:

-2

Step-by-step explanation:


Anastaziya [24]3 years ago
6 0
This would be 8 + -2 =6
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2/(x^2)=4/x+1<br>can any one solve this for me please
levacccp [35]
2/X^2=4/X+1                                   times by both denominators
2(x+1)=4(x^2)
2x+2=4x^2
4x^2-2x-2=0
(2x+1)(2x-2)=0
x=2x+1 or 2x-2
x=-1/2 or 1
5 0
4 years ago
What is the value of y?<br> 2y<br> Y+10<br> 50°
ASHA 777 [7]

Answer:

The question is incorrect. Please rewrite the question.

4 0
3 years ago
What is the value of the algebraic expression if x= 1/2 , y = -1, and z = 2? 6x(y2z) A. -12 B. -6 C. 1 D. 6
Free_Kalibri [48]
To determine the value of the given algebraic expression above, we simply substitute the values of each variable to the variables in the expression and evaluate the expression. We do as follows:

6x(y^2)(z)
      when x = 0.5
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                z = 2
6(0.5)((-1)^2)(2)
3(1)(2)
6

The value of the algebraic expression would be 6. An algebraic expression consists of variables which are represented with letters like for this case x, y and z, a coefficient which is indicated by numbers (e.g. 6 ) and exponents like 2 for the expression above. Often times expressions contains a number of terms which consists of those elements.
4 0
3 years ago
Which expression is equivalent to −3(−4m+9n)?
prohojiy [21]

Answer:

Yuhh the answers c dawhggg trus me i just did the same thing lawl!

Step-by-step explanation:

5 0
3 years ago
PRS is isosceles with RP RS RQ is drawn such that it bisects PRS What additional fact can be used to prove PRQ SRQ by Sas in ord
SOVA2 [1]

Answer:

\frac{PQR}{SQR}

Step-by-step explanation:

An isosceles triangle has two equal sides and the two opposite angles to the sides to be equal.

Given that; RP = RS, RQ and PS are common,

RP = SQ (opposite sides of parallelogram RPQS)

PQ = RS (opposite sides of parallelogram RPQS)

ΔRPS = ΔQPS (congruence property)

Thus comparing triangles PQR and SQR,

\frac{PQ}{SQ} = \frac{PR}{SR} (similarity property)

<PRS = <PRQ + <SRQ (bisection of included <PRS)

<PQS = <PQR + <SQR (similatity property to <PRS)

\frac{PRQ}{SRQ}  = \frac{SQR}{PQR} (congruence property)

But, SRQ = PQR

So that;

       \frac{PRQ}{SQR}

Therefore by Side-Angle-Side (SAS), the required additional fact is:  \frac{PRQ}{SQR}

8 0
3 years ago
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