How do you get the midpoint of a line segment? using shortcuts

Listed below are amounts of strontium-90 (in millibecquerels, or mBq) in a simple random sample of baby teeth obtained from r

Alenkinab [10]

Answer:

The 5-number summary is maximum= 175, minimum=126, median=150, Q₁=138 and Q₃=160.5.

Step-by-step explanation:

The given data set is

126, 128, 131, 135, 136, 140, 143, 145, 147, 148, 152, 154, 155, 156, 159, 162, 164, 166, 169, 175

The minimum value of the data is 126 and the maximum value of the data is 175.

Divide the data in two equal parts.

(126, 128, 131, 135, 136, 140, 143, 145, 147, 148), (152, 154, 155, 156, 159, 162, 164, 166, 169, 175)

The median of the data is

$Median=\frac{148+152}{2}=150$

Now divide each parenthesis in two equal parts.

(126, 128, 131, 135, 136), (140, 143, 145, 147, 148), (152, 154, 155, 156, 159), (162, 164, 166, 169, 175)

$Q_1=\frac{136+140}{2}=138$

$Q_3=\frac{159+162}{2}=160.5$

Therefore the 5-number summary is maximum= 175, minimum=126, median=150, Q₁=138 and Q₃=160.5.

8 0

4 years ago

"6. A brand name has a 40% recognition rate. Assume the owner of the brand wants to verify that rate by beginning with a small s

statuscvo [17]

Answer:

(a) The probability that exactly 5 of the 6 consumers recognize the brand name is 0.0369.

(b) The probability that all of the selected consumers recognize the brand name is 0.0041.

(c) The probability that at least 5 of the selected consumers recognize the brand name is 0.041.

(d) The events of 5 customers recognizing the brand name is unusual.

Step-by-step explanation:

Let X = number of consumer's who recognize the brand.

The probability of the random variable X is, P (X) = p = 0.40.

A random sample of size, n = 6 consumers are selected.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the value of P (X = 5) as follows:

$P(X=5)={6\choose 5}0.40^{5}(1-0.40)^{6-5}\\=6\times0.01024\times0.60\\=0.036864\\\approx0.0369$

Thus, the probability that exactly 5 of the 6 consumers recognize the brand name is 0.0369.

(b)

Compute the value of P (X = 6) as follows:

$P(X=6)={6\choose 6}0.40^{6}(1-0.40)^{6-6}\\=1\times 0.004096\times1\\=0.004096\\\approx0.0041$

Thus, the probability that all of the selected consumers recognize the brand name is 0.0041.

(c)

Compute the value of P (X ≥ 5) as follows:

P (X ≥ 5) = P (X = 5) + P (X = 6)

= 0.0369 + 0.0041

= 0.041

Thus, the probability that at least 5 of the selected consumers recognize the brand name is 0.041.

(d)

An event is considered unusual if the probability of its occurrence is less than 0.05.

The probability of 5 customers recognizing the brand name is 0.0369.

This probability value is less than 0.05.

Thus, the events of 5 customers recognizing the brand name is unusual.

8 0

4 years ago

Write as a decimal. If necessary, use a bar to indicate which digit or group of digits repeats

Gnoma [55]

2.83333333(repeating)

8 0

3 years ago

What is the difference between the point (6,-3) and (6,5)?

love history [14]

Answer:

6.4 this is the middle between them or like 0.1 is difference

5 0

3 years ago

Find the number that makes the ratio equivalent to 5:6. :66

choli [55]

Answer:

55 - you multiplied 6 by 11 to get 66 so you multiply by 5 by 11 to get 55.

4 0

3 years ago